1 条题解
-
5
#include <bits/stdc++.h> using namespace std; const int MAXN = 105; int dp[10005], price[MAXN][MAXN]; int main() { int t, n, m, ans; scanf("%d%d%d", &t, &n, &m); for (int i = 1; i <= t; ++i) for (int j = 1; j <= n; ++j) scanf("%d", &price[i][j]); ans = m; for (int i = 1; i < t; ++i) { memset(dp, ~0x3f, sizeof(dp)); dp[ans] = ans; for (int j = 1; j <= n; ++j) for (int k = ans; k >= price[i][j]; --k) dp[k - price[i][j]] = max(dp[k - price[i][j]], dp[k] + price[i + 1][j] - price[i][j]); int ma = 0; for (int j = 0; j <= ans; ++j) ma = max(ma, dp[j]); ans = ma; } cout << ans; return 0; }
- 1
信息
- ID
- 1345
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 1
- 标签
- 递交数
- 138
- 已通过
- 92
- 上传者