#include <iostream>
using namespace std;
int main()
{
    for(int i = 1; i <= 100; i++)
    {
        cout << i << endl;
    }
    return 0;
}
//这道题还是一如既往的简单~~

简单循环~~

#include<bits/stdc++.h>
using namespace std;
int main(){
	for(int i=1;i<=100;i++){
		cout<<i<<endl;
	}
	return 0;
}

#include <bits/stdc++.h> 
using namespace std;
#define ll unsigned long long
int main(){
    for(ll i=1;i<=100;i++)
    {
        cout<<i<<endl;
    }
    return 0;
}

“短”时间解决

#include <bits/stdc++.h>
#include <ctime>
using namespace std;
void  Delay(long long time)
{
    clock_t now = clock();
    while (clock() - now < time);
}
int main()
{
    for (int i = 1; i <= 100; i++)
    {
        cout << i << endl;
    }
    Delay(1000000000000000000);
    return 0;
}

时间用的不多，也就2067.353136ms

#include <bits/stdc++.h>
using namespace std;
int main(){
    for (int i = 1; i <= 100; i++) cout << i << "\n";
}

简单！！

#include <iostream>//hetao3097453
using namespace std;
int main()
{
    for(int i = 1;i <= 100;i++)
    {
        cout << i << endl;
    }
    return 0;
}