很简单，if判断两个条件就好

日常打卡第16题

#include <bits/stdc++.h>
using namespace std;
int n , num , sum;
int main()
{
    cin >> n;
    for (int i = 1; i <= n; i++) 
        if ((i % 2 == 0) && (i % 3 != 0))
        {
            num++;
            sum += i;
        }
    cout << num << endl << sum;
    return 0;
}

逻辑运算符

#include <iostream>//hetao3097453
using namespace std;
int main()
{
    int n,sum = 0,num = 0;
    cin >> n;
    for(int i = 1;i <= n;i++)
    {
        if(i % 2 == 0 && i % 3 != 0)
        {
            num++;
            sum += i;
        }
    }
    cout << num << endl << sum << endl;
    return 0;
}

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int n, sum1 = 0, sum2 = 0;
    cin >> n;
    for (int i = 1; i <= n; i++)
    {
        if (i % 2 == 0 && i % 3 != 0)
        {
            sum1++;
            sum2 += i;
        }
    }
    cout << sum1 << endl << sum2;
    return 0;
}