#include<bits/stdc++.h>
using namespace std;
int main()
{
    int k;
    cin>>k;
    bool f=1;
    for (int i=10000;i<=30000;i++)
        if (i%1000%k==0&&i/10%1000%k==0&&i/100%k==0)
        {
            cout<<i<<'\n';
            f=0;
        }
    if (f)
        cout<<"No";
    return 0;
}

#include<bits/stdc++.h>
using namespace std;
int n,m,a,b,c;
int main()
{
    cin>>n;
    for(int i=10000;i<=30000;i++)
    {    
        a=i/100;
        b=i%10000/10;
        c=i%1000;
        if(a%n==0&&b%n==0&&c%n==0)
        {
            cout<<i<<endl;
            m++;
        }
    }
    if(m==0)
    {
        cout<<"No";
    }
    return 0;
}

#include<bits/stdc++.h>
using namespace std;
int main()
{	//num计数满足条件的数的个数 
	int k, sub1, sub2, sub3, num = 0;
	cin >> k;
	//遍历10000到30000之间的五位数
	for(int i = 10000; i <= 30000; i++){
		sub1 = i/100;
		sub2 = i/10%1000;
		sub3 = i%1000;
		if(sub1%k == 0 && sub2%k == 0 && sub3%k == 0){
			cout << i << endl;
			num++;
		}
	} 
	//如果无解，则输出“no";
	if(num == 0){
		cout << "No";
	} 
	return 0;
}