#include <iostream>
using namespace std;
int main()
{
for(int i = 2;i <= 8;i+=2)
{
cout << i << "0" << i << endl;
cout << i << "1" << i << endl;
cout << i << "2" << i << endl;
cout << i << "3" << i << endl;
cout << i << "4" << i << endl;
cout << i << "5" << i << endl;
cout << i << "6" << i << endl;
cout << i << "7" << i << endl;
cout << i << "8" << i << endl;
cout << i << "9" << i << endl;
}
return 0;
}

没人写题解？

#include <bits/stdc++.h> 
using namespace std;
int main()
{
    for(int i = 100; i <= 999; i++)
    {
        int a, c;
        a = i / 100;
        c = i % 10;
        if(a == c and c % 2 == 0)
        {
            cout << i << endl;
        }
    }
    return 0;
}

方法：

#include <iostream>
using namespace std;
int main(){
    for(int i=100;i<=999;i++)if(i%2==0&&i/100==i%10)cout<<i<<endl;
    return 0;
}

#include <bits/stdc++.h> using namespace std; int main() { for (int i = 100;i < 1000;i++) { if ((i % 10 == i / 100) && (i % 2 == 0)) { cout << i << endl; } } return 0; }

半夜打卡第三题

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int n = 202;//最小的回文偶数是202
    while (1)
    {
        if (n > 898) break;//最大的回文偶数是898，大于898可以直接终止循环
        if ((n / 100 == n % 10) && (n % 2 == 0)) cout << n << endl;//如果百位等于各位且n为偶数，打印n
        n++;
    }
    return 0;
}

别问我为什么不用for👀️

#include <iostream> using namespace std; int main() { for(int i = 2;i <= 8;i+=2) { cout << i << "0" << i << endl; cout << i << "1" << i << endl; cout << i << "2" << i << endl; cout << i << "3" << i << endl; cout << i << "4" << i << endl; cout << i << "5" << i << endl; cout << i << "6" << i << endl; cout << i << "7" << i << endl; cout << i << "8" << i << endl; cout << i << "9" << i << endl; } return 0; }

#include<bits/stdc++.h>
using namespace std;
int main()
{
    for (int i=100;i<=999;i++)
        if (i%10==i/100&&i%2==0)
            cout<<i<<'\n';
    return 0;
}

#include <bits/stdc++.h>
using namespace std;
int main(){
    int a, b;
    for (int i = 202; i <= 898; i++){
        a = i % 10;
        b = i / 100;
        if (a == b && b % 2 == 0) cout << i << "\n";
    }
}