52 条题解

  • 92
    @ 2022-7-15 23:36:26

    这题就是无脑狂写if语句 突然发现Ctrl+CV 是真香😄

    #include <bits/stdc++.h> 
using namespace std;
int main()
{
    int n;
    cin >> n;
    if(n >= 10000 and n < 99999)
    {
        cout << "wan" << endl;
    }
    if(n >= 100000 and n < 999999)
    {
        cout << "shi wan" << endl;
    }
    if(n >= 1000000 and n < 9999999)
    {
        cout << "bai wan" << endl;
    }
    if(n >= 10000000 and n < 99999999)
    {
        cout << "qian wan" << endl;
    }
    if(n >= 100000000 and n < 999999999)
    {
        cout << "yi" << endl;
    }
    if(n >= 1000000000 and n < 9999999999)
    {
        cout << "shi yi" << endl;
    }
    return 0;
}

    编码不易😕，点赞走起👀️
    记得点赞再抱走奥😄

    • @ 2022-7-18 21:16:17

      。。。。。。

    • @ 2022-7-18 21:16:58

      @ 没有别的方法？

    • @ 2022-8-3 17:04:03

      假如输入是99999，会发生啥呢？ 首先第一个 n < 99999; 漂亮，正好不在范围; 剩下的更不用提了;

    • @ 2022-8-4 19:22:37

      @ hh,也是

    • @ 2022-8-21 14:48:30

      帮你改了一下

      #include <bits/stdc++.h> 
using namespace std;
int main()
{
    int n;
    cin >> n;
    if(n >= 10000 and n < 99999)
    {
        cout << "wan" << endl;
    }
    if(n >= 100000 and n < 999999)
    {
        cout << "shi wan" << endl;
    }
    if(n >= 1000000 and n < 9999999)
    {
        cout << "bai wan" << endl;
    }
    if(n >= 10000000 and n < 99999999)
    {
        cout << "qian wan" << endl;
    }
    if(n >= 100000000 and n < 999999999)
    {
        cout << "yi" << endl;
    }
    if(n >= 1000000000 and n < 9999999999)
    {
        cout << "shi yi" << endl;
    }
    return 0;
}
    • @ 2022-8-26 14:07:23

      @c++语法警告一次！&&

    • @ 2022-8-27 11:12:27

      你把它改成这样，写一个“=”的位置不就有了吗？

      #include <bits/stdc++.h> 
using namespace std;
int main(){
    int n;
    cin >> n;
    if(n >= 10000 and n <= 99999)cout << "wan";
    if(n >= 100000 and n <= 999999)cout << "shi wan";
    if(n >= 1000000 and n <= 9999999)cout << "bai wan";
    if(n >= 10000000 and n <= 99999999)cout << "qian wan";
    if(n >= 100000000 and n <= 999999999)cout << "yi";
    if(n >= 1000000000 and n<=9999999999)cout << "shi yi";
    return 0;
}
    • @ 2022-8-27 11:13:27

      and和&&意思一样呀？@

    • @ 2022-8-29 17:07:52

      uhhh。。。

    • @ 2022-9-1 22:06:42

      👍 👍 👍 👍 👍 点赞666666666

    • @ 2022-9-2 17:23:07

      dnndndnd

    • @ 2022-9-5 16:24:34

      #incude <iostream> using namespace std; int main() { long long n; cin >> n; if (n <= 10000) { cout << "wan"; } else if (n <= 100000) { cout << "shi wan"; } else if (n <= 1000000) { cout << "bai wan"; } else if (n <= 10000000) { cout << "qian wan"; } else if (n <= 10000000) { cout << "yi"; } else { cout << "shi yi"; } return 0; }@

    • @ 2023-6-24 10:37:45

      你这种一看就是纸上谈兵，没点经验，and和&&通用，or和||通用@

    • @ 2023-8-5 14:54:49

      这么火呀。。。。。。 《关于这段代码获得了42个赞和<编码不易😕，点赞走起👀️记得点赞再抱走奥😄>的两件事》

    • @ 2023-8-5 15:09:31

      /user/20302
      《关于《关于《关于《关于《关于《关于@hetao390640这件事》这件事》这件事》这件事》这件事》这件事》

    • @ 2023-8-5 15:10:57

      @太像俄罗斯套娃了

    • @ 2023-8-16 17:07:09

      如果输一个9999999999就不行了吧

    • @ 2023-8-18 8:44:49

      <=

    • @ 2023-8-23 10:19:20

      else if ( )也行

    • @ 2023-8-26 17:11:15

      啊对对对@

    • @ 2023-9-3 18:57:09

      @ &&和end一样啊

    • @ 2023-9-8 21:08:34

      牛

    • @ 2023-11-12 19:00:12

      用long long也可以

    • @ 2024-3-22 23:52:35

      最好用long long类型的，因为你输入的数会超过int的范围，也就是10的9次方

    • @ 2024-6-16 18:35:33

      `cpp

      using namespace std;
int main()
{
    string a;
    getline(cin, a);
    if (a.size() == 5) cout << "wan";
    else if (a.size() == 6) cout << "shi wan";
    else if (a.size() == 7) cout << "bai wan";
    else if (a.size() == 8) cout << "qian wan";
    else if (a.size() == 9) cout << "yi";
    else cout << "shi yi";
    return 0;
}
  • 29
    @ 2022-8-9 20:22:02

    各位观众姥爷们，来吧，我先讲讲题目，可以用string型字符串数组，然后用a.size()来判断几位数，然后用几个分支语句即可。比陈元杰简单，看看吧~

    #include <bits/stdc++.h>
using namespace std;
int main()
{
    string a;
    getline(cin, a);
    if (a.size() == 5) cout << "wan";
    else if (a.size() == 6) cout << "shi wan";
    else if (a.size() == 7) cout << "bai wan";
    else if (a.size() == 8) cout << "qian wan";
    else if (a.size() == 9) cout << "yi";
    else cout << "shi yi";
    return 0;
}

    最后，点个赞吧~~~~写个评论吧

  • 7
    @ 2023-8-5 14:39:59

    由于我学过的知识有限，只想出了这种死算方法。 如果要用这种方法，建议你们使用复制粘贴。:command C + command V , Windows:ctrl C + ctrl V

    #include <iostream>
using namespace std;
int main()
{
    int n;
    cin >> n;
    if (n < 100000)
    {
        cout << "wan" << endl;
    }
    else if (n < 1000000)
    {
        cout << "shi wan" << endl;
    }
    else if (n < 10000000)
    {
        cout << "bai wan" << endl;
    }
    else if (n < 100000000)
    {
        cout << "qian wan" << endl;
    }
    else if (n < 1000000000)
    {
        cout << "yi" << endl;
    }
    else
    {
        cout << "shi yi" << endl;
    }
    return 0;
}

    如果你们喜欢，可以点赞然后复制哟丶(^u^)—👍

  • 3
    @ 2023-12-2 18:56:18

    见识一下粗暴代码（非抄袭）

    #include<iostream>
using namespace std;
int main()
{
    int a;
    cin>>a;
    if(a/10000<=9)
    {
        cout<<"wan";
    }
    else if(a/100000<=9)
    {
        cout<<"shi wan";
    }
    else if(a/1000000<=9)
    {
        cout<<"bai wan";
    }
    else if(a/10000000<=9)
    {
        cout<<"qian wan";
    }
    else if(a/100000000<=9)
    {
        cout<<"yi";
    }
    else if(a/1000000000<=9)
    {
        cout<<"shi yi";
    }
    return 0;
}

    这个代码比较适合初学者。 制作不易，求点赞👍

    • 3
      @ 2023-8-16 10:41:57 
      #include <iostream>
using namespace std;
int main()
{
    int n;
    cin >> n;
    if(n / 100000 > 0)
    {
        if(n / 1000000 > 0)
        {
            if(n / 10000000 > 0)
            {
                if(n / 100000000 > 0)
                {
                    if(n / 1000000000 > 0)
                    {
                        cout << "shi yi";
                    }
                    else
                    {
                        cout << "yi";
                    }
                }
                else
                {
                    cout <<"qian wan";
                }
            }
            else
            {
                cout << "bai wan";
            }
        }
        else
        {
            cout << "shi wan";
        }
    }
    else
    {
        cout << "wan";
    }
    return 0;
}
      • 2
        @ 2023-9-2 15:16:18

        easy

        #include<bits/stdc++.h>
using namespace std;
int main(){
	int n;cin>>n;
	if(n>=10000&&n<100000){
		cout<<"wan";
	}else if(n>=100000&&n<1000000){
		cout<<"shi wan";
	}else if(n>=1000000&&n<10000000){
		cout<<"bai wan";
	}else if(n>=10000000&&n<100000000){
		cout<<"qian wan";
	}else if(n>=100000000&&n<1000000000){
		cout<<"yi";
	}else{
		cout<<"shi yi";
	}
	return 0;
}
        • 2
          @ 2023-8-29 15:39:13 
          #include<iostream>
using namespace std;
int main()
{
    long long n,num=0;
    cin>>n;
    for(int i=1;i<=10;i++)
    {
        if(n/10>=1)
        {
            n=n/10;
            num++;
        }
        else
        {
            break;
        }
    }
    for(int i=1;i<=1;i++)
    {
        if(num>=9)
        {
            cout<<"shi yi";
            break;
        }
        if(num>=8)
        {
            cout<<"yi";
            break;
        }
        if(num>=7)
        {
            cout<<"qian wan";
            break;
        }
        if(num>=6)
        {
            cout<<"bai wan";
            break;
        }
        if(num>=5)
        {
            cout<<"shi wan";
            break;
        }
        if(num>=4)
        {
            cout<<"wan";
            break;
        }
    }
    return 0;
}
          • 2
            @ 2023-8-26 10:32:17

            暴力判断即可

            #include <iostream>
using namespace std;
int main()
{
    int n;
    cin >> n;
    if (n >= 10000 and n <= 99999)
    {
        cout << "wan";
    }
    if (n >= 100000 and n <= 999999)
    {
        1cout << "shi wan";
    }
    if (n >= 1000000 and n <= 9999999)
    {
        cout << "bai wan";
    }
    if (n >= 10000000 and n <= 99999999)
    {
        cout << "qian wan";
    }
    if (n >= 100000000 and n <= 999999999)
    {
        cout << "yi";
    }
    if (n >= 1000000000 and n <= 9999999999)
    {
        cout << "shi yi";
    }
    return 0;
}
            • 2
              @ 2023-8-20 11:38:02

              数学题

              #include <iostream>
using namespace std;
int main()
{
    int n;
    cin>>n;
    if (n/1000000000!=0)
    {
        cout<<"shi yi";
    }
    else if(n/100000000!=0)
    {
        cout<<"yi";
    }
    else if(n/10000000!=0)
    {
        cout<<"qian wan";
    }
    else if(n/1000000!=0)
    {
        cout<<"bai wan";
    }
    else if(n/100000!=0)
    {
        cout<<"shi wan";
    }
    else
    {
        cout<<"wan";
    }
}
              • 2
                @ 2023-8-16 20:28:22

                简单，就是if else if else 语句 #include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; if(n/10000<10) { cout << "wan"; } else if(n/10000<100) { cout << "shi wan"; } else if(n/10000<1000) { cout << "bai wan"; } else if(n/10000<10000) { cout << "qian wan"; } else if(n/10000<100000) { cout << "yi"; } else { cout << "shi yi"; }

                return 0; }

                • 2
                  @ 2023-8-13 15:31:03

                  大概看了其他题解，发现我的好像有点不一样（ 用的是数位切分（应该是这么叫吧 反正能过 ~~（先赞后看好习惯~

                  #include <iostream>
using namespace std;
int main()
{
    int n;
    cin >> n;
    if (n / 1000000000 >= 1)
    {
        cout << "shi yi";
    }
    else if (n / 100000000 >= 1)
    {
        cout << "yi";
    }
    else if (n / 10000000 >= 1)
    {
        cout << "qian wan";
    }
    else if (n / 1000000 >= 1)
    {
        cout << "bai wan";
    }
    else if (n / 100000 >= 1)
    {
        cout << "shi wan";
    }
    else if (n / 10000 >= 1)
    {
        cout << "wan";
    }
    return 0;
}
                • 2
                  @ 2023-6-17 17:24:44 
                  #include <bits/stdc++.h> 
using namespace std;
int main()
{
    int n;
    cin >> n;
    if(n >= 10000 and n < 99999)
    {
        cout << "wan" << endl;
    }
    if(n >= 100000 and n < 999999)
    {
        cout << "shi wan" << endl;
    }
    if(n >= 1000000 and n < 9999999)
    {
        cout << "bai wan" << endl;
    }
    if(n >= 10000000 and n < 99999999)
    {
        cout << "qian wan" << endl;
    }
    if(n >= 100000000 and n < 999999999)
    {
        cout << "yi" << endl;
    }
    if(n >= 1000000000 and n < 9999999999)
    {
        cout << "shi yi" << endl;
    }
    return 0;
}
求点赞！！！
                  • 2
                    @ 2022-8-3 17:01:26

                    if？if是不可呢写的，这题没必要

                    #include <iostream>
using namespace std;
string out[15] = {
	"草","ge","shi","bai","qian",
	"wan","shi wan","bai wan","qian wan",
	"yi","shi yi","bai yi" , "qian yi","草"}; //分行美观，数组存每位输出什么
long long n , i = 1;//我管他int会不会出事，看着大直接long long
int m ;//几位数
int main(){
	cin >> n ;//n>=10000 所以0啥的不用单独处理
	while(i < n)
		i *= 10 , m ++;//i >= n自动跳出，这时m就是数的位数
	cout << out[m] ;//输出
	return 0 ;//你就说写的少不少吧
}

                    结合 @ 我又进行了修改

                    #include <iostream>
using namespace std;
string out[15] = {
	"草","ge","shi","bai","qian",
	"wan","shi wan","bai wan","qian wan",
	"yi","shi yi","bai yi" , "qian yi","草"};//同上
int main(){
	cin >> out[0] ;//0位置输入，不用再开一个string
	cout << out[out[0].length()] ;//string长度=位数
	//.length(),.size()都能获取长度，本质区别不大
    return 0;//行数少了，但还是3ms，不行啊
}

                    点赞再抱走奥

                    • @ 2023-8-5 15:19:03

                      如果是我，我会把这串字符写成{ "草","草","草","草","草","草","草","草","草","草","草",……(此处省略10^10字)} 开个玩笑，何必当真呢？

                    • @ 2023-8-20 11:41:00

                      我再次修改

                      using namespace std;
string out[15] = {
"草","ge","shi","bai","qian",
"wan","shi wan","bai wan","qian wan",
"yi","shi yi","bai yi" , "qian yi","草"};//同上
int main(){
cin >> out[0] ;
cout << out[out[0].length()] 
}
                  • 1
                    @ 2024-2-1 10:53:51 
                    #include <iostream>
using namespace std;
int main()
{
    long long a,num=0;
    cin>>a;
    while(a>0)
    {
        num++;
        a/=10;
    }
    if(num==5)
    {
        cout<<"wan";
    }
    if(num==6)
    {
        cout<<"shi wan";
    }
    if(num==7)
    {
        cout<<"bai wan";
    }
    if(num==8)
    {
        cout<<"qian wan";
    }
    if(num==9)
    {
        cout<<"yi";
    }
    if(num==10)
    {
        cout<<"shi yi";
    }
    return 0;
}
                    • 1
                      @ 2024-1-3 20:24:00

                      Ctrl+c/v用起来！！！（@陈元杰 都是复制if）

                      #include<bits/stdc++.h> 
using namespace std;
int main()
{
    int n;
    cin>>n;
    if(n >= 10000 and n < 99999)  {
        cout << "wan" << endl;
    }
    if(n >= 100000 and n < 999999)  {
        cout << "shi wan" << endl;
    }
    if(n >= 1000000 and n < 9999999)  {
        cout << "bai wan" << endl;
    }
    if(n >= 10000000 and n < 99999999)  {
        cout << "qian wan" << endl;
    }
    if(n >= 100000000 and n < 999999999)  {
        cout << "yi" << endl;
    }
    if(n >= 1000000000 and n < 9999999999)  {
        cout << "shi yi" << endl;
    }
    return 0;
}
                      • 1
                        @ 2023-12-29 18:54:31 
                        #include <bits/stdc++.h> 
using namespace std;
int main()
{
    int n;
    cin >> n;
    if(n >= 10000 and n < 99999)
    {
        cout << "wan" << endl;
    }
    if(n >= 100000 and n < 999999)
    {
        cout << "shi wan" << endl;
    }
    if(n >= 1000000 and n < 9999999)
    {
        cout << "bai wan" << endl;
    }
    if(n >= 10000000 and n < 99999999)
    {
        cout << "qian wan" << endl;
    }
    if(n >= 100000000 and n < 999999999)
    {
        cout << "yi" << endl;
    }
    if(n >= 1000000000 and n < 9999999999)
    {
        cout << "shi yi" << endl;
    }
    return 0;
}
                        • 1
                          @ 2023-12-4 18:18:20

                          #include <iostream> using namespace std; int main() { int n; cin >> n;//这个不要漏 if (n < 100000)//if语句判断，以此类推 { cout << "wan" << endl;//通过判断，进行输出 } else if (n < 1000000) { cout << "shi wan" << endl; } else if (n < 10000000) { cout << "bai wan" << endl; } else if (n < 100000000) { cout << "qian wan" << endl; } else if (n < 1000000000) { cout << "yi" << endl; } else { cout << "shi yi" << endl; } return 0; }//

                          • 1
                            @ 2023-11-29 19:59:03 
                            #include <iostream>
using namespace std;
int main()
{
    int x;
    cin >>x;
    if (x<10)
    {
        cout <<"ge";
    }
    if (x>=10)
    {
        if (x<=99)
        {
            cout <<"shi";
        }
    }
    if (x>=100)
    {
        if (x<=999)
        {
            cout <<"bai";
        }
    }
    if (x>=1000)
    {
        if (x<=9999)
        {
            cout <<"qian";
        }
    }
    if (x>=10000)
    {
        if (x<=99999)
        {
            cout <<"wan";
        }
    }
    if (x>=100000)
    {
        if (x<=999999)
        {
            cout <<"shi wan";
        }
    }
    if (x>=1000000)
    {
        if (x<=9999999)
        {
            cout <<"bai wan";
        }
    }
    if (x>=10000000)
    {
        if (x<=99999999)
        {
            cout <<"qian wan";
        }
    }
    if (x>=100000000)
    {
        if (x<=999999999)
        {
            cout <<"yi";
        }
    }
    if (x>=1000000000)
    {
        if (x<=9999999999)
        {
            cout <<"shi yi";
        }
    }
    if (x>=10000000000)
    {
        if (x<=99999999999)
        {
            cout <<"bai yi";
        }
    }
    if (x>=100000000000)
    {
        if (x<=999999999999)
        {
            cout <<"qian yi";
        }
    }
    if (x>=1000000000000)
    {
        if (x<=9999999999999)
        {
            cout <<"zhao";
        }
    }
    return 0;
}

                            以AC，可以放心食用

                            • 1
                              @ 2023-11-29 19:57:23

                              #include <iostream> using namespace std; int main() { int x; cin >>x; if (x<10) { cout <<"ge"; } if (x>=10) { if (x<=99) { cout <<"shi"; } } if (x>=100) { if (x<=999) { cout <<"bai"; } } if (x>=1000) { if (x<=9999) { cout <<"qian"; } } if (x>=10000) { if (x<=99999) { cout <<"wan"; } } if (x>=100000) { if (x<=999999) { cout <<"shi wan"; } } if (x>=1000000) { if (x<=9999999) { cout <<"bai wan"; } } if (x>=10000000) { if (x<=99999999) { cout <<"qian wan"; } } if (x>=100000000) { if (x<=999999999) { cout <<"yi"; } } if (x>=1000000000) { if (x<=9999999999) { cout <<"shi yi"; } } if (x>=10000000000) { if (x<=99999999999) { cout <<"bai yi"; } } if (x>=100000000000) { if (x<=999999999999) { cout <<"qian yi"; } } if (x>=1000000000000) { if (x<=9999999999999) { cout <<"zhao"; } } return 0; }

                              以AC，可以放心食用^^ ** _

                              • 1
                                @ 2023-11-22 19:54:57

                                这题就是无脑狂写if语句 突然发现Ctrl+CV 是真香😄

                                #include <bits/stdc++.h> 
using namespace std;
int main()
{
    int n;
    cin >> n;
    if(n >= 10000 and n < 99999)
    {
        cout << "wan" << endl;
    }
    if(n >= 100000 and n < 999999)
    {
        cout << "shi wan" << endl;
    }
    if(n >= 1000000 and n < 9999999)
    {
        cout << "bai wan" << endl;
    }
    if(n >= 10000000 and n < 99999999)
    {
        cout << "qian wan" << endl;
    }
    if(n >= 100000000 and n < 999999999)
    {
        cout << "yi" << endl;
    }
    if(n >= 1000000000 and n < 9999999999)
    {
        cout << "shi yi" << endl;
    }
    return 0;
}

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                                【入门】求数的量级？

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                                ID
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                                时间
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                                内存
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