数据不大，适合打表//娱乐用

#include <cstdio>
using namespace std;
int a[150] , l , r ;
void get(){//打表，就100多个数罢了，枚举所有可行的数
	a[0] = 1017 , a[1] = 1023 , a[2] = 1024 , a[3] = 1027 , a[4] = 1028 ;
	a[5] = 1036 , a[6] = 1037 , a[7] = 1042 , a[8] = 1113 , a[9] = 1117 ;
	a[10] = 1164 , a[11] = 1175 , a[12] = 1176 , a[13] = 1197 , a[14] = 1228 ;
	a[15] = 1267 , a[16] = 1268 , a[17] = 1277 , a[18] = 1302 , a[19] = 1307 ;
	a[20] = 1323 , a[21] = 1328 , a[22] = 1343 , a[23] = 1352 , a[24] = 1355 ;
	a[25] = 1375 , a[26] = 1395 , a[27] = 1405 , a[28] = 1428 , a[29] = 1433 ;
	a[30] = 1441 , a[31] = 1442 , a[32] = 1444 , a[33] = 1463 , a[34] = 1541 ;
	a[35] = 1593 , a[36] = 1594 , a[37] = 1628 , a[38] = 1646 , a[39] = 1648 ;
	a[40] = 1701 , a[41] = 1706 , a[42] = 1746 , a[43] = 1791 , a[44] = 1816 ;
	a[45] = 1866 , a[46] = 1873 , a[47] = 1896 , a[48] = 1903 , a[49] = 1921 ;
	a[50] = 1936 , a[51] = 1949 , a[52] = 1953 , a[53] = 1964 , a[54] = 1976 ;
	a[55] = 1991 , a[56] = 1996 , a[57] = 2013 , a[58] = 2027 , a[59] = 2069 ;
	a[60] = 2095 , a[61] = 2123 , a[62] = 2126 , a[63] = 2175 , a[64] = 2199 ;
	a[65] = 2203 , a[66] = 2277 , a[67] = 2301 , a[68] = 2304 , a[69] = 2311 ;
	a[70] = 2321 , a[71] = 2322 , a[72] = 2326 , a[73] = 2339 , a[74] = 2382 ;
	a[75] = 2396 , a[76] = 2401 , a[77] = 2414 , a[78] = 2439 , a[79] = 2493 ;
	a[80] = 2507 , a[81] = 2509 , a[82] = 2527 , a[83] = 2528 , a[84] = 2529 ;
	a[85] = 2547 , a[86] = 2552 , a[87] = 2553 , a[88] = 2557 , a[89] = 2595 ;
	a[90] = 2599 , a[91] = 2618 , a[92] = 2672 , a[93] = 2684 , a[94] = 2686 ;
	a[95] = 2699 , a[96] = 2701 , a[97] = 2711 , a[98] = 2727 , a[99] = 2731 ;
	a[100] = 2801 , a[101] = 2802 , a[102] = 2821 , a[103] = 2825 , a[104] = 2866 ;
	a[105] = 2882 , a[106] = 2884 , a[107] = 2905 , a[108] = 2911 , a[109] = 2927 ;
	a[110] = 2929 , a[111] = 2931 , a[112] = 2945 , a[113] = 2984 , a[114] = 2992 ;
	a[115] = 3018 , a[116] = 3041 , a[117] = 3042 , a[118] = 3059 , a[119] = 3094 ;
	a[120] = 3105 , a[121] = 3111 , a[122] = 3142 ; 
}
int main(){
	scanf("%d%d",&l,&r);
	get();
	for(int i = 0 ; a[i] <= r ; i ++)
		if(a[i] >= l)
			printf("%d\n",a[i]) ;//输出！
	/*freopen("a.txt","w", stdout);//打表代码，保存在"a.txt" 不会真有人手打吧
	int m = 0 ;
	for(int i = 1000 ; i <= 9999 ; i ++){
		long x = i * i ;
		int a[10] = {};
		if(x >= 10000000)
			break ;
		while(x){
			a[x%10] ++ ;
			if(a[x%10] > 1)
				break ;
			x /= 10 ;
		}
		if(!x){
			printf("a[%d] = %d ", m ++ , i) ;
			if(m % 5 == 0)
				printf(";\n	") ;
			else
				printf(", ") ;
		}
	}*/
	
	return 0 ;
}

#include <bits/stdc++.h>
using namespace std;
bool nna(int dude)
{
    int lll = dude * dude;
    int a[10];
    for (int i = 1 ; i <= 7 ; i++)
    {
        a[i] = lll % 10;
        lll /= 10;
    }
    int sum = true;
    int cnt = 0;
    
    
    for (int i = 1 ; i <= 7 ; i++)
    {
        for(int j = 1 ; j <= 7 ; j++)
        {
            if (a[i] == a[j])
            {
                cnt++;
            }
        }
        if (cnt == 7)
        {
            sum = false;
        }
        else
        {
            sum = true;
        }
    }
    return sum;
}
int main()
{
    int x , y;
    cin >> x >> y;
    for (int i = x ; i <= y ; i++)
    {
        if(nna(i) == false)
        {
            cout << i << endl;
        }
    }
    return 0;
}

#include <iostream>
#include <cmath>
using namespace std;
void judge(int i)
{
	int a[7];
	int g = i * i;
	int work = 1;
	if (i * i / 1000000 != 0)//一定要是七位数
	{
		for (int j = 0; j < 7; j++)
		{
			a[j] = (g - g / (int)pow(10, j+1) * (int)pow(10, j+1)) / (int)pow(10, j);//获取各个数位，可以参考1083回文数
		}
		for (int i = 0; i < 7; i++)
		{
			for (int j = i + 1; j < 7; j++)
			{
				if (a[i] == a[j])
				{
					work = 0;
				}
			}
		}
		if (work == 1)
		{
			cout << i << endl;
		}
	}
}
int main() 
{
	int a, b;
	cin >> a >> b;
	for (int i = a; i <= b; i++)
	{
		judge(i);
	}
	return 0;
}

//简单枚举
#include <bits/stdc++.h>
using namespace std;
bool f(int x){
    bool vis[10]={};
    while (x){//判断是否有重复的数位
        if (vis[x%10]){
            return 0;
        }
        vis[x%10]=1;
        x/=10;
    }
    return 1;
}
int main(){
    int x,y;
    cin>>x>>y;
    for (int i=x;i<=y;i++){
        if (10000000>i*i&&i*i>999999&&f(i*i)){
            cout<<i<<endl;
        }
    }
    return 0;
}

简朴的代码

#include<bits/stdc++.h>
using namespace std;
int x,y,a[10];
void awa()
{
    for (int i=0;i<=9;i++)
        a[i]=0;
    return;
}
bool qwq()
{
    for (int i=0;i<=9;i++)
        if (a[i]>1)
            return 0;
    return 1;
}
int main()
{
    cin>>x>>y;
    for (int i=x;i<=y;i++)
    {
        if (i*i<1000000||i*i>9999999)
            continue;
        awa();
        a[(i*i)/1000000]++,a[(i*i)/100000%10]++,a[(i*i)/10000%10]++,a[(i*i)/1000%10]++,a[(i*i)/100%10]++,a[(i*i)/10%10]++,a[(i*i)%10]++;
        if (qwq())
            cout<<i<<'\n';
    }
    return 0;
}