#include <iostream>
using namespace std;

int main()
{
    char b[26] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'}; // 字母表定义
    int a;
    cin >> a;
    cout << static_cast<char>(toupper(b[a-1])) /*输出字母表位于a-1位置的字符的大写*/ << " " << b[a-1];
}

有可能有点繁琐，但似乎没有其他方法了^[1]