3 条题解
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4
#include <bits/stdc++.h> #define ll long long using namespace std; const int N=2e5+5; const int p=998244353; ll ksm(ll a,ll b){ll s=1,m=a; while(b){if(b&1)s=s*m%p; m=m*m%p,b>>=1;} return s;} ll m,n,x,y,ans,fc[N],ifc[N]; ll C(ll m,ll n){return fc[n+m-1]*ifc[n]%p*ifc[m-1]%p;} int main(){ cin>>m>>n>>x>>y; fc[0]=1; for(int i=1;i<=m+n;i++)fc[i]=fc[i-1]*i%p; ifc[m+n]=ksm(fc[m+n],p-2); for(int i=m+n-1;~i;i--)ifc[i]=ifc[i+1]*(i+1)%p; if(x<=n&&y>n)for(int i=1;i<=m;i++)ans=(ans+C(i,x-1)*C(m-i+1,n-x)%p*C(m-i+1,y-n-1)%p*C(i,2*n-y))%p; else ans=C(m,n)*C(m,n+x-y)%p; cout<<ans<<endl; return 0; }
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-5
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#include <bits/stdc++.h> #define ll long long
using namespace std;
const int N=2e5+5; const int p=998244353; ll ksm(ll a,ll b){ll s=1,m=a; while(b){if(b&1)s=sm%p; m=mm%p,b>>=1;} return s;}
ll m,n,x,y,ans,fc[N],ifc[N]; ll C(ll m,ll n){return fc[n+m-1]ifc[n]%pifc[m-1]%p;}
int main(){ cin>>m>>n>>x>>y; fc[0]=1; for(int i=1;i<=m+n;i++)fc[i]=fc[i-1]i%p; ifc[m+n]=ksm(fc[m+n],p-2); for(int i=m+n-1;~i;i--)ifc[i]=ifc[i+1](i+1)%p; if(x<=n&&y>n)for(int i=1;i<=m;i++)ans=(ans+C(i,x-1)C(m-i+1,n-x)%pC(m-i+1,y-n-1)%pC(i,2n-y))%p; else ans=C(m,n)*C(m,n+x-y)%p; cout<<ans<<endl; return 0; }
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信息
- ID
- 1801
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 1
- 标签
- 递交数
- 77
- 已通过
- 55
- 上传者