四种不同结果的题解~

已AC，请放心食用

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int o, s, x = 1000, n = 0;
    cin >> o;
    s = o;
    while (s > 0)
    {
        n += s % 10 * x;
        s /= 10;
        x /= 10;
    }
    cout << o - n;
    return 0;
}

已WA，请小心食用

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int o, s, x = 1000, n = 0;
    cin >> o;
    s = o;
    while (s > 0)
    {
        n += s % 10 * x;
        s /= 10;
        x /= 10;
    }
    cout << n - o;
    return 0;
}

已TLE，请小心食用

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int o, s, x = 1000, n = 0;
    cin >> o;
    s = o;
    while (s > 0)
    {
        n += s % 10 * x;
        n /= 10;
        x /= 10;
    }
    cout << o - n;
    return 0;
}

已RE，请小心食用

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int o, s, x = 1000, n = 0;
    cin >> o;
    s = o;
    while (s > 0)
    {
        n += s % 10 * x;
        s / 10;
        x / 10;
    }
    cout << o - n;
    return 0;
}

#include <iostream>//hetao3097453
#include <cmath>
using namespace std;
int main()
{
    int n,sum = 0,num = 0;
    cin >> n;
    int a = n / 1000;
    int b = n / 100 % 10;
    int c = n / 10 % 10;
    int d = n % 10;
    sum += a * 1 + b * 10 + c * 100 + d * 1000;
    num = n - sum;
    cout << num << endl;
    return 0;
}

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int a,n,x,y,z,sum=0;
    cin>>a;
    n=a*0.001;
    x=a*0.01-10*n;
    y=a*0.1-100*n-10*x;
    z=a-1000*n-100*x-10*y;
    sum=1000*z+100*y+10*x+n;
    cout<<a-sum;
    return 0;
}

#include <iostream>
using namespace std;
int main(){
    char a[4];
    cin>>a[0]>>a[1]>>a[2]>>a[3];
    cout<<(a[0]-'0')*1000+(a[1]-'0')*100+(a[2]-'0')*10+(a[3]-'0')-(a[3]-'0')*1000-(a[2]-'0')*100-(a[1]-'0')*10-(a[0]-'0');
    return 0;
}

字符串

#include <bits/stdc++.h>
using namespace std;
int main()
{
    string s;
    cin >> s;
    int a = (s[0] - '0'), b = (s[1] - '0'), c = (s[2] - '0'), d = (s[3] - '0');
    int ans1 = a * 1000 + b * 100 + c * 10 + d;
    int ans2 = d * 1000 + c * 100 + b * 10 + a;
    cout << ans1 - ans2 << endl;
    return 0;
}

#include <bits/stdc++.h>
using namespace std;
int sum,n;
int main()
{
    cin>>n;
    sum+=n/1000+n/100%10*10+n/10%10*100+n%10*1000;
    cout << n-sum << endl;
    return 0;
}

#include <iostream>
using namespace std;
int main()
{
	int a;
	cin >> a;
	cout << a - (a % 10 * 1000 + a / 10 % 10 * 100 + a / 100 % 10 * 10 + a / 1000);
	return 0;
}