#include <bits/stdc++.h>
using namespace std;
int main()
{
	int n, a, b, c;
	cin >> n >> a >> b >> c;
	if (n >= a + b + c)
        cout << n - (a + b + c) << " " << "YES";
	else
        cout << abs(n - (a + b + c)) << " " << "NO";
	return 0;
}//代码已AC

我代码最短

#include <iostream>
#include <cmath>
using namespace std;
int main()
{
    int n, a, b, c;
    cin >> n >> a >> b >> c;
    int ans = (a + b + c);
    cout << abs(n - ans);
    cout << ((n >= ans) ? " YES" : " NO");
    return 0;
}

#include <iostream>
using namespace std;
int main()
{
    int n,a,b,c;
    cin >> n >>a >> b >> c;
    if(n>=a+b+c)
    {
        cout << n-(a+b+c) << " " << "YES";
    }
    else
    {
        cout << (a+b+c)-n << " " << "NO";
    }
}

(感觉跟P361差不多)

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n,x,y,z;
    cin>>n>>x>>y>>z;
    if (n>=x+y+z)
        cout<<n-x-y-z<<" YES";
    else
        cout<<x+y+z-n<<" NO";
    return 0;
}