先建一个string数组a，然后存入1~9的单词，判断n是否大于9，是就输出out，不是就输出a[n-1]

参考代码（已AC）：

#include <bits/stdc++.h>
using namespace std;
int n;
string a[9]={"one","two","three","four","five","six","seven","eight","nine"};
int main()
{
    cin>>n;
    if(n>9)
        cout<<"out";
    else
        cout<<a[n-1];
    return 0;
}

#include<iostream>
using namespace std;
int main()
{
	int n;
	cin>>n;
	if(n>0 && n<10)
	{
	    if(n==1)
	     cout<<"one";
	    else if(n==2)
	     cout<<"two";
	    else if(n==3)
	     cout<<"three";	
	    else if(n==4)
	     cout<<"four";	
	    else if(n==5)
	     cout<<"five";	
	    else if(n==6)
	     cout<<"six";	
	    else if(n==7)
	     cout<<"seven";	
	    else if(n==8)
	     cout<<"eight";	
	    else if(n==9)
	     cout<<"nine";	
	}
	else
	{
		cout<<"out";
	}
	return 0;
}

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int c;
    cin >> c;
    if(c == 1)
    {
        cout << "one";
    }
    else if (c == 2)
    {
        cout << "two";
    }
    else if (c == 3)
    {
        cout << "three";
    }
    else if (c == 4)
    {
        cout << "four";
    }
    else if (c == 5)
    {
        cout << "five";
    }
    else if (c == 6)
    {
        cout << "six";
    }
    else if (c == 7)
    {
        cout << "seven";
    }
    else if (c == 8)
    {
        cout << "eight";
    }
    else if (c == 9)
    {
        cout << "nine";
    }
    else
    {
        cout << "out";
    }
    return 0;
}

原始算法 A

这道题就是无脑判断…… 话不多说，直接上代码！

#include <bits/stdc++.h>
using namespace std;
int n;
int main()
{
    cin >> n;
    if (n == 1)
    {
        cout << "one";
    }
    else if (n == 2)
    {
        cout << "two";
    }
    else if (n == 3)
    {
        cout << "three";
    }
    else if (n == 4)
    {
        cout << "four";
    }
    else if (n == 5)
    {
        cout << "five";
    }
    else if (n == 6)
    {
        cout << "six";
    }
    else if (n == 7)
    {
        cout << "seven";
    }
    else if (n == 8)
    {
        cout << "eight";
    }
    else if (n == 9)
    {
        cout << "nine";
    }
    else
    {
        cout << "out";
    }
    return 0;
}

最简

#python
a = {1 : 'one', 2 : 'two', 3 : 'three', 4 : 'four', 5 : 'five', 6 : 'six', 7 : 'seven', 8 : 'eight', 9 : 'nine'}
b = int(input())
if b in a:
    print(a[b])
else:
    print('out')

最简

#include<bits/stdc++.h>
using namespace std;
int main()
{
    string s[10]={"0","one","two","three","four","five","six","seven","eight","nine"};
    int n;
    cin>>n;
    if (n<=9)
        cout<<s[n];
    else
        cout<<"out";
    return 0;
}

题不难，就是耗时间 最笨最简单的方法：

#include <iostream>
using namespace std;
int main()
{
    int n;
    cin >> n;
    if(n > 9)//如果大于九，输出“out”
    {
        cout << "out";
    }
    else
    {
        if(n == 1)//一
        {
            cout << "one";
        }
        if(n == 2)//二
        {
            cout << "two";
        }
        if(n == 3)//三
        {
            cout << "three";
        }
        if(n == 4)//四
        {
            cout << "four";
        }
        if(n == 5)//五
        {
            cout << "five";
        }
        if(n == 6)//六
        {
            cout << "six";
        }
        if(n == 7)//七
        {
            cout << "seven";
        }
        if(n == 8)//八
        {
            cout << "eight";
        }
        if(n == 9)//九
        {
            cout << "nine";
        }
    }
    return 0;
}

号没了

#include <iostream>
using namespace std;
int main()
{
    int n;
    cin >> n;
    if(n>9)
    {
        cout << "out";
    }
    else
    {
        if(n==1)
        {
            cout << "one";
        }
        if(n==2)
        {
            cout << "two";
        }
        if(n==3)
        {
            cout << "three";
        }
        if(n==4)
        {
            cout << "four";
        }
        if(n==5)
        {
            cout << "five";
        }
        if(n==6)
        {
            cout << "six";
        }
        if(n==7)
        {
            cout << "seven";
        }
        if(n==8)
        {
            cout << "eight";
        }
        if(n==9)
        {
            cout << "nine";
        }
    }
}

#include<cstdio> using namespace std; int main() { int a; scanf("%d",&a); if((a>=1)&&(a<=9)) { switch(a) { case 1:printf("one")break;; case 2:printf("two");break; case 3:printf("three");break; case 4:printf("four");break; case 5:printf("five");break; case 6:printf("six");break; case 7:printf("seven");break; case 8:printf("eight");break; case 9:printf("nine"); } } return 0; }