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#include<bits/stdc++.h>
using namespace std;
int n,x,y;
int main()
{
    cin>>n>>x>>y;
    for(int i=1;i<=n/x;i++)
    {
        for(int j=1;j<=n/y;j++)
        {
            if(i+j>50&&i*x+j*y==n)
            {
                cout<<i<<" "<<j<<endl;
            }
        }
    }
    return 0;
}

``

中于用python解出来了！！！！

a = [int(i) for i in input().split()]
n = a[0]
x = a[1]
y = a[2]
xi = n / x
yi = n / y
xi= int(xi)
yi = int(yi)
for i in range(xi):
    for j in range(yi):
  
        if i + j > 50 and i * x + y * j == n:
            if i != 0 and j != 0:
                print(i,j)

#include<bits/stdc++.h>
using namespace std;
int main()
{
	int n, x, y, t;
	cin >> n >> x >> y;
	//枚举篮球的购买范围
	for(int i = 1; i <= (n - y) / x; i++){
		//计算剩余的钱
		t = n - i * x;
		if(t % y == 0 && i + t / y > 50){
			cout << i << " " << t / y << endl;
		} 
	} 
	return 0;
}