easy 只是二维列表

已AC，放心食用

#include<bits/stdc++.h>
using namespace std;
int main(){
    int n,i,j;
    cin>>n;
    int a[n][n];
    for(i=0;i<n;i++){
        for(j=0;j<n;j++){
            a[i][j]=1;
            if(i==n/2&&j==n/2) a[i][j]=0;
            if(i+j==n/2||i-j==n/2||j-i==n/2||i+j==(n/2-1+n)) a[i][j]=0;
        printf("%3d",a[i][j]);
        }
        cout<<endl;
    } 
    return 0;
}