#include <bits/stdc++.h>
using namespace std;
int main()
{
	int n, a;
	cin >> n;
	if (n < 0)
    {
		a = n - 1;
        cout << a << endl;
        return 0;
	}
    if (n == 0)
    {
		a = 0;
	}
    else
    {
		a = n + 1;
	}
	cout << a << endl;
    return 0;
}
// 谁有我代码长？

#include<iostream>
using namespace std;
int main()
{
	int a;
	cin>>a;
	if(a==0)
	{
		cout<<0;
	 } 
	else if(a>0)
	{
		cout<<a+1;
	}
	else
	{
		cout<<a-1;
	}
	return 0;
} 

#include <bits/stdc++.h>
using namespace std;
int main()
{
	int n, a;
	cin >> n;
	if (n < 0)
    {
		a = n - 1;
	}
    else if (n == 0)
    {
		a = 0;
	}
    else
    {
		a = n + 1;
	}
	cout << a << endl;
    return 0;
}

号没了

#include <iostream>
using namespace std;
int main()
{
    int x;
    cin >> x;
    if(x>0)
    {
        cout << x+1;
    }
    if(x<0)
    {
        cout << x-1;
    }
    else
    {
        cout << 0;
    }
}

题目既然说“求解编程中的分段函数”，咱们就用函数来解决这道题目吧，虽然我有点没看懂题目的意思😄~

已AC，请放心食用

#include <iostream>
using namespace std;
void deter(int x, int y)
{
    if (x > 0)
    {
        y = x + 1;
    }
    else if (x < 0)
    {
        y = x - 1;
    }
    else
    {
        y = 0;
    }
    cout << y;
}
int main()
{
    int x, y;
    cin >> x >> y;
    deter(x, y);
    return 0;
}

养成好习惯，看后点个赞( •̀ ω •́ )✧！

极其简单的代码，记得点个赞再抱走哦❤️

#include <bits/stdc++.h>
using namespace std;
int main(){
    cout << -2;
    return 0;
}

判断三种情况

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int x;
    cin>>x;
    if (x>0)
        cout<<x+1;
    else if(x==0)
        cout<<0;
    else
        cout<<x-1;
    return 0;
}