2 条题解
-
1
#include <iostream> using namespace std; int main() { int n; cin >> n; int x = n * n, a[n][n]; for (int i = 1; i <= n; i++) { for (int j = 1; j <= n; j++) { a[i][j] = x; x--; if (a[i][j] / 10 == 0) { cout << " " << a[i][j]; } else { cout << " " << a[i][j]; } } cout << endl; } return 0; }
- 1
信息
- ID
- 188
- 时间
- 1000ms
- 内存
- 16MiB
- 难度
- 1
- 标签
- 递交数
- 88
- 已通过
- 63
- 上传者