枚举判断

已AC，放心食用

#include<bits/stdc++.h>
using namespace std;
int n,s;
char a[100002][8];
int main(){
    scanf("%d",&n);
    for(int i=1;i<=n;++i)
        cin>>a[i];
    for(int i=1;i<=n;++i)
        if((a[i][0]>='A'&&a[i][0]<='G')||(a[i][0]>='R'&&a[i][0]<='T')) 
            s++;
    printf("%d",n-s);
    return 0;
}

#include<iostream>
using namespace std;
int n,num;
string x;
int main(){
    cin>>n;
    for(int i=1;i<=n;i++){
        cin>>x;
        if(x[0]=='A'||x[0]=='B'||x[0]=='C'||x[0]=='D'||x[0]=='E'||x[0]=='F'||x[0]=='G'||x[0]=='R'||x[0]=='S'||x[0]=='T')
            num++;
    }
    cout<<num;
    return 0;
}

这是真AC代码

#include<bits/stdc++.h>
using namespace std;
int main(){
    cout<<1;
    return 0;
}

#include<bits/stdc++.h>
using namespace std;
string s[10005];
int num,n;
int main()
{
    cin>>n;
    for(int i=1;i<=n;i++)
    {
        cin>>s[i];
        if((s[i][0]>='A'&&s[i][0]<='G')||(s[i][0]>='R'&&s[i][0]<='T')) 
        {  
            num++;
        }

    }
    cout<<n-num;
    return 0;
}