AC代码

#include <bits/stdc++.h>
using namespace std;
int main() 
{
    char a[7], b[7];
    cin >> a >> b;
    int a_mul = 1, b_mul = 1, a_len = strlen(a), b_len = strlen(b);
    for (int i = 0; i < a_len; i++)
        a_mul *= a[i] - 'A' + 1;
    for (int i = 0; i < b_len; i++)
        b_mul *= b[i] - 'A' + 1;
    if (a_mul % 47 == b_mul % 47)
        cout << "GO";
    else
        cout << "STAY";
    return 0;
}

#include<iostream>
#include<cstring>
using namespace std;
const int MOD=47;//定义常量
string a,b;
int sa=1,sb=1;//不是那个意思……
int main(){
    cin>>a>>b;
    int la=a.length();
    int lb=b.length();
    for(int i=0;i<la;i++)
        sa*=int(a[i]-'A'+1);
    for(int i=0;i<lb;i++)
        sb*=int(b[i]-'A'+1);
    if(sa%MOD==sb%MOD)
        cout<<"GO";
    else
        cout<<"STAY";
    return 0;
}//编者：Royal

看见大神们的题解，只能憋出3个字：看不懂...... 于是乎——我决定推出自己菜鸟般的题解(简单易懂)：

#include<iostream>
using namespace std;
string s1,s2;
int plus_char(string s){
    int n=1;
    for(int i=0;i<s.length();i++){
        char c=s[i];
        n*=c-64;
    }
    return n;
}
int main(){
    cin>>s1>>s2;
    int n1=plus_char(s1)%47,n2=plus_char(s2)%47;
    if(n1==n2)  cout<<"GO";
    else  cout<<"STAY";
    return 0;
}

10行搞定

#include<bits/stdc++.h>
using namespace std;
int main(){
    char a[7], b[7];
    cin>>a>>b;
    int a_mul=1,b_mul=1,a_len=strlen(a),b_len=strlen(b);
    for(int i=0;i<a_len;i++)a_mul*=a[i]-'A'+1;
    for(int i=0;i<b_len;i++)b_mul*=b[i]-'A'+1;
    cout<<(a_mul%47==b_mul%47?"GO":"STAY");
}

已AC