这一道题非常简单，在这里为大家提供三种方法，至于选哪种，你自己选择O(∩_∩)O~

已AC，请放心食用

方法1：普通法

#include <bits/stdc++.h>
using namespace std;
int main()
{
    char a;
    cin >> a;
    cout << a << a << a << a << endl;
    cout << a << "  " << a << endl;
    cout << a << "  " << a << endl;
    cout << a << a << a << a;
    return 0;
}

方法2：合并法

#include <iostream>
using namespace std;
int main()
{
    char a;
    cin >> a;
    cout << a << a << a << a << endl << a << " " << " " << a << endl;
    cout << a << " " << " " << a << endl << a << a << a << a;
    return 0;
}

方法3：函数法

#include <iostream>
using namespace std;
void line(char n)
{
    for (int i = 1; i <= 4; i++)
    {
        cout << n;
    }
    cout << endl;
}
void mid(char n)
{
    cout << n << "  " << n << endl;
}
int main()
{
    char n;
    cin >> n;
    line(n);
    mid(n);
    mid(n);
    line(n);
    return 0;
}

养成好习惯，看后点个赞😎！

Accepted 0.547999ms 6984KiB

#include <bits/stdc++.h>
using namespace std;
char a;
int main()
{
    cin >> a;
    cout << a << a << a << a << endl;
    cout << a << "  " << a << endl;
    cout << a << "  " << a << endl;
    cout << a << a << a << a;
    return 0;
}

代码已AC,请放行食用

#include <iostream>
using namespace std;
int main()
{
    char a;
    cin >> a;
    cout << a << a << a << a << endl << a << " " << " " << a << endl;
    cout << a << " " << " " << a << endl << a << a << a << a;
    return 0;
}

#include <iostream>//hetao3097453
using namespace std;
int main()
{
    char a;
    cin >> a;
    cout << a << a << a << a << endl;
    cout << a << "  " << a << endl;
    cout << a << "  " << a << endl;
    cout << a << a << a << a << endl;
    return 0;
}

#include<bits/stdc++.h> using namespace std; int main() { char x; cin>>x; for (int i=1;i<=4;i++) { for (int j=1;j<=4;j++) { if (((i3)||(i2))&&((j3)||(j2))) { cout<<" "; } else { cout<<x; } } cout<<endl; } return 0; }