1 条题解
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1
#include <iostream> #include <cstring> #include <queue> using namespace std; const int N = 110; struct Node { int x, y, z; }; char g[N][N][N]; int dist[N][N][N]; int L, R, C, x1, y1, z1, x2, y2, z2; int dx[6] = {-1, 0, 1, 0, 0, 0}; int dy[6] = {0, 1, 0, -1, 0, 0}; int dz[6] = {0, 0, 0, 0, -1, 1}; int bfs() { memset(dist, -1, sizeof dist); queue<Node> q; q.push({x1, y1, z1}); dist[x1][y1][z1] = 0; while(q.size()) { Node t = q.front(); q.pop(); if(t.x == x2 && t.y == y2 && t.z == z2) return dist[t.x][t.y][t.z]; for (int i = 0; i < 6; i ++) { int a = t.x + dx[i], b = t.y + dy[i], c = t.z + dz[i]; if(a < 1 || a > L || b < 1 || b > R || c < 1 || c > C) continue; if(g[a][b][c] == '#' || dist[a][b][c] != -1) continue; q.push({a, b, c}); dist[a][b][c] = dist[t.x][t.y][t.z] + 1; } } return -1; } int main() { while(cin >> L >> R >> C, L || R || C) { for (int i = 1; i <= L; i ++) for (int j = 1; j <= R; j ++) for (int k = 1; k <= C; k ++) { cin >> g[i][j][k]; if(g[i][j][k] == 'S') x1 = i, y1 = j, z1 = k; if(g[i][j][k] == 'E') x2 = i, y2 = j, z2 = k; } if(bfs() == -1) cout << "Trapped!" << endl; else cout << "Escaped in " << dist[x2][y2][z2] << " minute(s)." << endl; } return 0; }
或
#include<iostream> #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<string> #include<cstdlib> #include<queue> #include<vector> #define INF 0x3f3f3f3f #define PI acos(-1.0) #define N 101 #define MOD 2520 #define E 1e-12 using namespace std; int X,Y,Z; char a[N][N][N]; bool vis[N][N][N]; int dir[6][3]={{1,0,0},{-1,0,0},{0,1,0},{0,-1,0},{0,0,1},{0,0,-1}}; struct node { int x; int y; int z; int step; }q[N*10000]; void bfs(int sx,int sy,int sz,int ex,int ey,int ez) { int head=1,tail=1; bool flag=true; memset(vis,0,sizeof(vis)); vis[sx][sy][sz]=1; q[tail].x=sx; q[tail].y=sy; q[tail].z=sz; q[tail].step=0; tail++; while(head<tail) { int x=q[head].x; int y=q[head].y; int z=q[head].z; int step=q[head].step; if(x==ex&&y==ey&&z==ez) { flag=false; printf("Escaped in %d minute(s).\n",step); break; } for(int i=0;i<6;i++) { int nx=x+dir[i][0]; int ny=y+dir[i][1]; int nz=z+dir[i][2]; if(0<=nx&&nx<X&&0<=ny&&ny<Y&&0<=nz&&nz<Z&&a[nx][ny][nz]=='.'&&vis[nx][ny][nz]==0) { vis[nx][ny][nz]=1; q[tail].x=nx; q[tail].y=ny; q[tail].z=nz; q[tail].step=step+1; tail++; } } head++; } if(flag) printf("Trapped!\n"); } int main() { int sx,sy,sz,ex,ey,ez; while(scanf("%d%d%d",&X,&Y,&Z)!=EOF&&X&&Y&&Z) { for(int i=0;i<X;i++) for(int j=0;j<Y;j++) scanf("%s",a[i][j]); for(int i=0;i<X;i++) for(int j=0;j<Y;j++) for(int k=0;k<Z;k++) { if(a[i][j][k]=='S') { sx=i; sy=j; sz=k; } if(a[i][j][k]=='E') { ex=i; ey=j; ez=k; a[i][j][k]='.'; } } bfs(sx,sy,sz,ex,ey,ez); } return 0; }
- 1
信息
- ID
- 424
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 9
- 标签
- 递交数
- 11
- 已通过
- 5
- 上传者