#include<bits/stdc++.h>
using namespace std;
int main(){
    int n,a=0,b=0,c=0;
    cin>>n;
    for (int i=1;i<=n;i++)
    {
        int x;
        cin>>x;
        a+=x;
        cin>>x;
        b+=x;
        cin>>x;
        c+=x;
    }
    cout<<a<<" "<<b<<" "<<c<<" "<<a+b+c;
    return 0;
}
*有一亿点简单，自己看去吧。
别走，先点个赞再说。

#include <iostream>

using namespace std;

int main()
{
    int n;
    cin >> n;

    int gold = 0, silver = 0, bronze = 0;
    for (int i = 0; i < n; ++i) {
        int g, s, b;
        cin >> g >> s >> b;
        gold += g;
        silver += s;
        bronze += b;
    }

    cout << gold << " " << silver << " " << bronze << " " << gold+silver+bronze << endl;

    return 0;
}

#include <iostream> using namespace std; int main() { int n,a,b,c; int a1=0,b1=0,c1=0,s; cin >> n; //确定输入天数 while(n--) //循环n天 { cin>>a>>b>>c; //每天的金银铜 a1+=a; //金牌累加 b1+=b; //银牌累加 c1+=c; //铜牌累加 } s=a1+b1+c1; //奖牌总和 cout<<a1<<" "<<b1<<" "<<c1<<" "<<s; //输出金银铜总数 中间空格 return 0; }

#include <iostream>//太简单了我只能说
using namespace std;
int main()
{
    int n;
    cin >> n;
    int sum = 0;
    int gold=0;
    int ying = 0;
    int tong =0;
    for(int i = 1;i<=n;i++)
    {
        int a,b,c;
        cin >>  a>>b>>c;
        gold+=a;
        ying+=b;
        tong+=c;
        
    }
    sum = (gold+ying+tong);
    cout << gold <<" "<<ying<<" "<<tong<<" "<<sum;
    return 0;
}