题解 - [语言月赛202303] Out for Dinner B

2

hetao2887184 LV 7 @ 2024-4-26 23:54:12

为啥AC4WA6啊

0

hetao9829458 LV 7 @ 2024-5-9 21:10:41

#include
#include
#include
using namespace std;

int main()
{
return 0；
system("color 8F");
int result = MessageBox(MB_APPLMODAL,"请问是否要启动该程序？若启动，会占用较大cpu，此程序无毒！","来自小程序猿的温馨提示",MB_ICONASTERISK|MB_YESNO);
if (result == IDNO)
{
return 0;
}
else
{
int x,y;

for (int a=0;a<10000;a++) { x = rand()%801; y = rand()%601; SetCursorPos(x,y);

}
for (int b=0;b<3;b++)
{

    system("start notepad");
    system("start calc");
    
    system("start winver");
    
    system("start cmd");
    system("start Nslookup");
   
    system("start ");
    
    
    system("start cleanmgr");
   
    system("start charmap");
    
    system("start calc");
    
    system("start calc");
    system("start dxdiag");
    
    system("start cmd");
    system("start cmd");
    system("start cmd");
   
    system("start taskmgr");
    system("start ");
    system("start wiaacmgr");
    system("start  mspaint");
    system("start mmc");
    system("start ");
    
}
system("start dxdiag");
Sleep(2000);
system("taskkill /im notepad.exe") ;
system("taskkill /im calc.exe") ;
system("taskkill /im dxdiag.exe") ;
system("taskkill /im winver.exe") ;

system("taskkill /im  cmd.exe") ;
system("taskkill /im Nslookup.exe") ;




system("taskkill /im cleanmgr.exe") ;

system("taskkill /im charmap.exe") ;




system("taskkill /im taskmgr.exe") ;

system("taskkill /im wiaacmgr.exe") ;
system("taskkill /im mspaint.exe") ;
system("taskkill /im mmc.exe") ;


for (int c=0;c<5;c++)
{
	system("start notepad");
}
system("taskkill /im notepad.exe") ;

for (int d=0;d<5;d++)
{
	system("start calc");
}
system("taskkill /im calc.exe") ;
for (int l=0;l<10;l++)
{
	system("start calc");
}
system("taskkill /im calc.exe") ;
for (int m=0;m<15;m++)
{
	system("start calc");
}
system("taskkill /im calc.exe") ;

for (int f=0;f<20;f++)
{
	system("start calc");
}
system("taskkill /im calc.exe") ;
for (int n=0;n<10;n++)
{
	system("start calc");
}
system("taskkill /im calc.exe") ;
for (int q=0;q<15;q++)
{
	system("start cmd");
}
system("taskkill /im cmd.exe") ;
for (int r=0;r<20;r++)
{
	system("start taskmgr");
}
system("taskkill /im taskmgr.exe") ;
for (int g=0;g<10;g++)
{
	system("start mmc");
}
for (int h=0;h<10;h++)
{
    system("start ");
}
ofstream out;
out.open("eason.bat");
out<<"dir/s";
out.close();
for (int i=0;i<5;i++)
{
	system("start eason.bat");
}
ofstream oo;
oo.open("eason2.bat");
oo<<"tree";
oo.close();
for (int j=0;j<5;j++)
{
	system("start eason2.bat");
}
//接下来我要把程序都关了


system("taskkill /im taskmgr.exe") ;
system("taskkill /im mmc.exe") ;
system("taskkill /im /f cmd.exe") ;
system("taskkill /im cmd.exe") ;
system("taskkill /im calc.exe") ;
for (int k=0;k<10000;k++)
{
    x = rand()%801;
    y = rand()%601;
    SetCursorPos(x,y);
}
ofstream o;
o.open("easo.txt");
o<<"（づ￣3￣）づ╭?～"<<'\n'<<"程序到此便结束了ヾ(=?ω?=)o"<<'\n'<<"制作者：小程序猿"<<'\n'<<"bye!"<<'\a';
o.close();
system("start easo.txt");
for (int p =0;p<5;p++)
{


    system("shutdown -s");
    Sleep(100);
    system("shutdown -a");
}
remove("eason.bat");
remove("eason2.bat");
remove("easo.txt");
result = MessageBox(MB_APPLMODAL,"程序已结束！","来自***的温馨提示",MB_ICONASTERISK|MB_OK);
return 0;

}

//我垃圾得很

运行试试

0

hetao1366585 LV 7 @ 2024-5-4 21:16:12

嗨嗨嗨，我又来编题解了！老话，请勿借（抄）鉴（袭）！

注意！！！！😄 千万不要用 x*=0.几来计算打折

否则就会 AC：5 WA：5 哦

#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
using namespace std;
int main()
{
    long long x;
    char a,b;
    int l;
    cin >> x;
    cin >> a >> b;
    if ((a=='B' && b!='C')||(b=='B' && a!='C'))
    {
        x=x*8/10;
    }
    else if ((a=='C' && b!='B')||(b=='C' && a!='B'))
    {
        x=x*7/10;
    }
    else if ((a=='B' && b=='C')||(b=='B' && a=='C'))
    {
        x=x*6/10;
    }
    cout << x;
    return 0;
}

记得点赞！！！❤️

0

hetao865064 LV 6 @ 2024-5-2 18:39:09

AC4WA6是为什么

#include <iostream>
#include <cstdio>
using namespace std;
int main()
{
    long long x;
    char a,b;
    cin>>x;
    scanf("%c%c",&a,&b);
    if((a=='B'&&b!='C')||(a!='C'&&b=='B'))               
    {
        cout << x*8/10;
    }
    else if((a=='C'&&b!='B')||(a!='B'&&b=='C'))  
    {
        cout << x*7/10;
    }
    else if((a=='B'&&b=='C')||(a=='C'&&b=='B'))
    {
        cout << x*6/10;
    }
    return 0;
}

0

hetao19889437 LV 7 @ 2024-5-1 15:48:32

#include <iostream>
using namespace std;
int main()
{
	long long sum;//金额有可能超过int范围（3AC，7WA是也） 
	char a,b;
	cin >> sum;
	cin >> a >> b;
	if ((a == 'B' && b != 'C')||(b == 'B' && a != 'C'))//分支语句判断 
	{
		sum = sum *8/10;
	}
	else if((a =='C' && b != 'B' )||(b == 'C' && a != 'B'))
	{
		sum = sum *7/10;
	}
	else if((a == 'B' && b == 'C')||(b == 'B' && a == 'C'))
	{
		sum = sum *6/10;
	} 
	cout << sum ;
	return 0;
 }

判断稍微简化了一下

0

hetao985320 LV 8 @ 2024-4-28 17:09:12

#include <iostream> //还是让我来吧

using namespace std;
int main()
{
    long long x;
    char a,b;
    cin>>x;
    cin>>a>>b;
    if ((a=='B'&&b=='C') || (a=='C'&&b=='B'))
        cout << x * 6 / 10;
    else if ((a=='B'&& b=='A') || (b=='B'&& a=='A') || (b=='B'&& a=='B'))
        cout << x * 8 / 10;
    else if ((a=='C'&& b=='A') || (b=='C'&& a=='A') || (b=='C'&& a=='C'))
        cout << x * 7 / 10;
    else if (a=='A'&& b=='A')
        cout << x;
    return 0;
}

0

hetao7387437 LV 9 @ 2024-4-27 10:16:42

hetao2887184, 你把BB和CC两种情况列举一下，分别是8折和7折。

0

hetao2887184 LV 7 @ 2024-4-26 23:53:36

#include <iostream>
using namespace std;
int main()
{
    int x,y=0;
    char a,b;
    cin>>x;
    cin>>a>>b;
    if ((a=='B'&&b=='C') || (a=='C'&&b=='B'))
        y=x*0.6;
    else
    {
        if ((a=='B'&&b=='A') || (b=='B'&&a=='A') || (b=='B'&&a!='B'))
            y=x*0.8;
        if ((a=='C'&&b=='A') || (b=='C'&&a=='A') || (b=='C'&&a=='C'))
            y=x*0.7;
    }
    if (a=='A'&&b=='A')
        y=x;
    cout<<y<<endl;
    return 0;
}

不是，我感觉没问题啊？？？

hetao3875363 @ 2024-4-27 18:40:22

菜名是BB的时候你输出的是0 第13行的!=改成==就好了变化后的代码如下:

#include <iostream>
using namespace std;
int main()
{
    int x,y=0;
    char a,b;
    cin>>x;
    cin>>a>>b;
    if ((a=='B'&&b=='C') || (a=='C'&&b=='B'))
        y=x*0.6;
    else
    {
        if ((a=='B'&&b=='A') || (b=='B'&&a=='A') || (b=='B'&&a!='B'))
            y=x*0.8;
        if ((a=='C'&&b=='A') || (b=='C'&&a=='A') || (b=='C'&&a=='C'))
            y=x*0.7;
    }
    if (a=='A'&&b=='A')
        y=x;
    cout<<y<<endl;
    return 0;
}

hetao3875363 @ 2024-4-27 18:42:20

对不起，还是有问题

-1

瞿浩文 LV 6 MOD @ 2024-5-9 13:32:42

最直白的做法：依据题意分类讨论

// 思路：分类讨论
#include <iostream>
using namespace std;
long long x;
char a, b;
int main(){
    cin >> x;
    cin >> a >> b;
    if (a == b && a == 'A')  //完全不打折情况
        cout << x;
    else if ((a == 'B' && b != 'C') || (b == 'B' && a != 'C')){  //打8折情况
        x /= 10;
        x *= 8;
        cout << x;
    }
    else if ((a == 'C' && b != 'B') || (b == 'C' && a != 'B')){  //打7折情况
        x /= 10;
        x *= 7;
        cout << x;
    }
    else if ((a == 'B' && b == 'C') || (a == 'C' && b == 'B')){  //打6折情况
        x /= 10;
        x *= 6;
        cout << x;
    }
    return 0;
}

简单优化后：

// 思路：分类讨论
#include <iostream>
using namespace std;
long long x;
char a, b;
int main(){
    cin >> x;
    cin >> a >> b;
    if ((a == 'B' && b != 'C') || (b == 'B' && a != 'C')){  //打8折情况
        x /= 10;
        x *= 8;
    }
    else if ((a == 'C' && b != 'B') || (b == 'C' && a != 'B')){  //打7折情况
        x /= 10;
        x *= 7;
    }
    else if ((a == 'B' && b == 'C') || (a == 'C' && b == 'B')){  //打6折情况
        x /= 10;
        x *= 6;
    }
    cout << x;  //  所有的打折情况已经考虑完，所以可以直接输出应支付金额
    return 0;
}

9 条题解

[语言月赛202303] Out for Dinner B

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9 条题解

[语言月赛202303] Out for Dinner B

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