#include<iostream>
using namespace std;
int main()
{
    int n,x,d=1;
    cin>>n>>x;
    cout<<"+---------------------+"<<endl;
    for(int i=1;i<=n+x-1;i+=1)
    {
        if(i%7==1)cout<<"|";
        if(i<=x-1)cout<<"...";
        else
        {
            if(d<10)cout<<".."<<d;
            else cout<<"."<<d;
            d+=1;
        }
        if(i%7==0)cout<<"|"<<endl;
    }
    if((n+x-1)%7!=0)
    {
        for(int i=1;i<=7-(n+x-1)%7;i+=1)cout<<"...";
        cout<<"|"<<endl;
    }
    cout<<"+---------------------+"<<endl;
}

这题 貔(pi) 条件真多

#include <bits/stdc++.h>
using namespace std; 
int main(){
    string a[20]; int n,x; cin>>n>>x; 
    int q=n-8+x; q=q<0?0:q;
    int h=ceil(q/7.0)+2;
    a[0]=a[h]="+---------------------+\n";
    for(int i=1;i<h;i++)a[i]="|.....................|\n";
    for(int i=1;i<=n;i++,x++){
        x=x%8?x:x+1;
        if(i<10)a[x/8+1][3*(x%8)]=i+'0';
        else a[x/8+1][3*(x%8)-1]=i/10+'0',
             a[x/8+1][3*(x%8)]=i%10+'0';}
    for(int i=0;i<h+1;i++)cout<<a[i];
    return 0;}