怪好玩的

LTC 这题的题号挺6啊 好了不废话了上代码🚀️ 来了个简单点的

#include<iostream>
using namespace std;//注释
int main()
{
int n;
string a[7]={"swim","rest","program","rest","read","math","rest"};
cin>>n;
cout<<a[n-1];
return 0;
}

#include <bits/stdc++.h>
using namespace std;

int main() {
    int n;
    char a[7][5] = {
        "swim",
        "rest",
        "prog",
        "rest",
        "read",
        "math",
        "rest",
    };
    cin >> n;
    cout << (n-1)[a];
    if (n == 3) cout << "ram";
    return 0;
}

#include <iostream>
using namespace std;
int main()
{
    int n;
    cin >> n;
    if (n == 1)
    {
        cout << "swim" << endl;
    }
    else if (n == 3)
    {
        cout << "program" << endl;
    }
    else if (n == 5)
    {
        cout << "read" << endl;
    }
    else if (n == 6)
    {
        cout << "math" << endl;
    }
    else
    {
        cout << "rest" << endl;
    }
    return 0;
}

#include <iostream> //当然可以用万能头
using namespace std;
int main()
{
    int n;
    cin >> n;
    if (n == 1)
    {
        cout << "swim";
    }
    if (n == 3)
    {
        cout << "program";
    }
    if (n == 5)
    {
        cout << "read";
    }
    if (n == 6)
    {
        cout << "math";
    }
    if (n == 2 or n == 4 or n == 7) //逝逝用else😕 
    {
        cout << "rest";
    }
    return 0;
}

这道题如果所有的判断都是if那么当你输入1时，你会得到一个大大的swimrest，但如果我们在之后的3个if千加上else它就变成了else if这样这道题就对了代码如下：

#include<bits/stdc++.h>
using namespace std;
int main(){
	int n;cin>>n;
	if(n==1){
		cout<<"swim";
	}
	else if(n==3){
		cout<<"program";
	} 
	else if(n==5){
		cout<<"read";
	} 
	else if(n==6){
		cout<<"math";
	}else{
		cout<<"rest";
	}
	return 0;
}

编码不易，点个赞吧😄

#include <bits/stdc++.h>
using namespace std;

int main()
{
    int a;
    cin >> a;
    if(a == 1)//周一
    {
        cout << "swim";
    }
    else if(a == 3)//周三
    {
        cout << "program";
    }
    else if(a == 5)//周五
    {
        cout << "read";
    }
    else if(a == 6)//周六
    {
        cout << "math";
    }
    else//其它
    {
        cout << "rest";
    }
    return 0;
}

#include <iostream>
using namespace std;
int main()
{
    int a;
    cin>>a;
    if (a==1)
    {
        cout<<"swim";
    }
    else if(a==3)
    {
        cout<<"program";
    }
    else if (a==5)
    {
        cout<<"read";
    }
    else if (a==6)
    {
        cout<<"math";
    }
    else
    {
        cout<<"rest";
    }
    return 0;
}

全网最笨方法

//hetao29146用户
#include <iostream>
using namespace std;
int main()
{
    int a;
    cin>>a;
    if (a==1) //判断是否是星期一
        cout<<"swim"<<endl;
    else
        if (a==3)  //判断是否是星期三
			cout<<"program"<<endl;
        else
            if (a==5) //判断是否是星期五
				cout<<"read";
            else 
                if (a==6) //判断是否是星期六
					cout<<"math";
                else 
					cout<<"rest";
}

#include <iostream>
using namespace std;

int main() {
    int day;
    cin >> day;

    switch (day) {//这个语句很高级，作用相当于if判断，可以省去if的麻烦
        case 1:
            cout << "swim" << endl;
            break;
        case 3:
            cout << "program" << endl;
            break;
        case 5:
            cout << "read" << endl;
            break;
        case 6:
            cout << "math" << endl;
            break;
        default:
            cout << "rest" << endl;
    }

    return 0;
}

    int n;
    cin >> n;
    bool a,b,c,d;//不懂了看我上一题的题解
    a = (n == 1);
    b = (n == 3);
    c = (n == 5);
    d = (n == 6);
    if (a)//接下来判断
    {
        cout << "swim";
    }
    else if (b)//else if是“否则 如果（判断）”
    {
        cout << "program";
    }
    else if (c)
    {
        cout << "read";
    }
    else if (d)
    {
        cout << "math";
    }
    else
    {
        cout << "rest";
    }

</span>

这题也能用布尔！

点赞！！！

（此代码来之不易，是原创，先点赞吧！）

OK呀，也是AC好吧。

#include <bits/stdc++.h>
using namespace std;
int main()
{
    long long n;
    cin>>n;
    if (n==1)
        cout<<"swim";
    else if (n==3)
        cout<<"program";
    else if (n==5)
        cout<<"read";
    else if (n==6)
        cout<<"math";
    else
        cout<<"rest";
    return 0;
}

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int x;
    cin>>x;
    if (x==1)
        cout<<"swim";
    else if (x==3)
        cout<<"program";
    else if (x==5)
        cout<<"read";
    else if (x==6)
        cout<<"math";
    else
        cout<<"rest";
    return 0;
}

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int n;//定义
    cin >> n;//输入
    if (n==1)//周一
    {
        cout << "swim";
    }
    else if (n==3)//周三
    {
        cout << "program";
    }
    else if (n==5)//周五
    {
        cout << "read";
    }
    else if (n==6)//周六
    {
        cout << "math";
    }
    else//其他时候
    {
        cout << "rest";
    }
    return 0;
}

#include <iostream>
using namespace std;
int main()
{
    int n;
    cin>>n;
    if (n==1)
    {
        cout<<"swim";
    }
    else   #这里多套几次if--else也行
    {
        if(n==3)
        {
            cout<<"program";
        }
        else
        {
            if(n==5)
            {
                cout<<"read";
            }
            else
            {
                if(n==6)
                {
                    cout<<"math";
                }
                else
                {
                    cout<<"rest";
                }
            }
        }    
    }
    return 0;
}

#include <iostream>
using namespace std;
int main()
{
    int n;
    cin>>n;
    if (n==1)
    {
        cout<<"swim";
    }
    else#这里多套几次if——else也可以
    {
        if(n==3)
        {
            cout<<"program";
        }
        else
        {
            if(n==5)
            {
                cout<<"read";
            }
            else
            {
                if(n==6)
                {
                    cout<<"math";
                }
                else
                {
                    cout<<"rest";
                }
            }
        }    
    }
    return 0;
}

这道题一如既往的简单,
我的方法也简单粗暴。
只要你不怕累,就可以定义一个string数组a,
然后赋值......
话不多说,上代码！

#include<iostream>
#include<string>
using namespace std;
string a[8];
int main()
{
    for (i = 1; i <= 7; i++)
    {
        a[i] = "rest";
    }
    a[1] = "swim";
    a[3] = "program";
    a[5] = "read";
    a[6] = "math";  //换成 a = {"e", "swim", "rest", "program", "rest", "read", "math", "rest"}也可以;
    int b;
    cin >> b;
    cout << a[b] << endl;
    re turn 0; 
}

小盆友们，您学会了吗？

复制？
代码不易，先点赞，再复制吧！
（不要忘了删倒数第二行的空格!)

#include <iostream> using namespace std; int main() { int n; cin >> n; if(n1) { cout<<"swim"; } if(n3) { cout<<"program"; } if(n5) { cout <<"read"; } if(n6) { cout<<"math"; } if(n2) { cout<<"rest"; } if(n4) { cout<<"rest"; } if(n==7) { cout <<"rest"; } return 0; } 先点赞再看！！！！！

#include <bits/stdc++.h>//惯用万能头，万事皆从头。（笑） 
using namespace std;
int main()
{
    long long n;//long long一在，谁都不爱；long long出征，寸草不生。
    cin >> n;
    if(n == 1)//用if,else if,else判断，来确定输出。
    {
        cout << "swim";
    }
    else if(n == 3) 
    {
        cout << "program";
    }
    else if(n == 5) 
    {
        cout << "read";
    }
    else if(n == 6)
    {
        cout << "math";
    }
    else//这里如果用else，不会出错，因为用的是if,else if,else;
    { 
        cout << "rest";
    }
    return 0;
}

谢谢大家的讲解