嘻嘻，简洁的代码来喽！！

#include<bits/stdc++.h>
using namespace std;
int main(){
    int a , b;
    cin >> a >> b;
    if(a == b) cout << "Y" << endl;
    else cout << "N" << endl;
    cout << a * b;
    return 0;
}

using namespace std;
int main()
{
    int a,b;
    cin>>a>>b;
    if(a==b)
    {
        cout<<"Y"<<endl;
    }
    else
    {
        cout<<"N"<<endl;
    }
    cout<<a*b;
    return 0;
}

#include<iostream>
using namespace std;

int main()
{
    int a,b;
    cin>>a>>b;
    if(a==b)
    {
        cout<<"Y"<<endl<<a*b;
    }
    else
    {
        cout<<"N"<<endl<<a*b;
    }

    return 0;
}
+

先判断两边是否相等，分别输出“Y”和“N” 然后再输出a*b的积（面积）

```
#include <bits/stdc++.h>
using namespace std;
int main()
{
    int a;
    cin >> a;
    if (a == 1) cout << "swim";
    else if (a == 3) cout << "program";
    else if (a == 5) cout << "read";
    else if (a == 6) cout << "math";
    else cout << "rest";
    return 0;
}
```

#include <bits/stdc++.h> using namespace std; int a, b; int main() { cin >> a >> b; if(a != b) { cout << "N" << endl << a * b; } else { cout << "Y" << endl << a * b; } return 0; }

#include <iostream> using namespace std; int main() { int a,b; cin >> a >> b; if (a == b) { cout << "Y" << endl; cout << a * b << endl; } else { cout << "N" << endl; cout << a * b << endl; } return 0; }

这题挺简单的 话不多说，直接上代码(由于太懒，不想多打字，所以只上中间代码)

int a , b; cin >> a >> b if (a = b) { cout << "Y" << end l << a * b; } else { cout<< "N" << endl << a * b ; } (由于害怕复制，所以故意错了一点，请谅解😄 )

#include <iostream>
#include <cstdio>

using namespace std;

int main()
{
    int width, height;
    scanf("%d %d", &width, &height);

    cout << ((width == height) ? "Y\n" : "N\n") << width * height << endl; // 三元运算符，嘿嘿~~~

    return 0;
}

++点赞数量，球球惹~~~

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int a,b;
    cin>>a>>b;
    if(a==b)
    {
        cout<<"Y"<<endl;//正方形的特性：两条边相等；所以如果相等输出Y;
    }
    else
    {
        cout<<"N"<<endl;
    }
    cout<<a*b;
    return 0;
}

这是我第一次发评论``` #include <iostream> using namespace std; int main() { int x,y; cin>>x>>y; if (x==y) { cout<<"Y"<<endl; } else { cout<<"N"<<endl; } cout<<x*y; return 0; }

#include <iostream>
using namespace std;
int main()
{
    int x,y;
    cin>>x>>y;
    if (x==y)
    {
        cout<<"Y"<<endl;
    }
    else
    {
        cout<<"N"<<endl;
    }
    cout<<x*y;
    return 0;
}

最后别忘了return 0

#include <iostream>
using namespace std;
int main()
{
    int a,b;
    cin>>a>>b;
    if (a==b)
    {
        cout<<"Y"<<endl;
    }
    else
    {
        cout<<"N"<<endl;
    }
    cout<<a*b;
    return 0;
}

瓦的电脑快没电了>_<

#include <iostream>
using namespace std;
int main()
{
    int x,y;
    cin>>x>>y;
    if (x==y)
    {
        cout<<"Y"<<endl;
    }
    else
    {
        cout<<"N"<<endl;
    }
    cout<<x*y;
}

//这道题挺简单的，就是用一个if语句加上输出就行了，来，上代码！
#include<iostream>
using namespace std;
int main()
    {
    int a,b;
    cin>>a>>b;
    if(a==b)
    {
        cout<<"Y"<<endl<<a*b;
    }
    else
    {
        cout<<"N"<<endl<<a*b;
    }
    return 0;
}

//编码不易，先点赞，在抱走哦😄 

#include <iostream>
using namespace std;
int main()
{
	int a,b;
    cin>>a>>b;
    if(a==b)
     {
        cout<<"Y"<<endl;
        cout<<a*b;
     }
     else
     {
        cout<<"N"<<endl;
        cout<<a*b;
     }   
	return 0;
}

#include <bits/stdc++.h>
using namespace std;

int main() {
    int a, b;
    cin >> a >> b;
    if (a - b)
        cout << "N";
    else
        cout << "Y";
    cout << endl << a * b;
    return 0;
}

#include <bits/stdc++.h> using namespace std; int main() { int a,b; cin >> a >> b; if (a==b)//判断条件 { cout <<"Y"<<endl;//注意引号 } else { cout <<"N"<<endl; } cout << a*b; return 0; }

#include <bits/stdc++.h>
    using namespace std;
    int main()
    {
        //               *** 
        //              *****
        //               ***
        //             ********
        //           **  ****** **
        //           **  ****** **
        //               ******
        //             **** ****
        //            ***    ***
        //            ***     ***
        int a,b;
        cin >> a >> b;
        if (a==b)
        {
            cout <<"Y"<<endl;
        }
        else
        {
            cout <<"N"<<endl;
        }
        cout << a*b;
        return 0;
    }

#include <iostream>
using namespace std;
int main()
{
    int i,k;
    cin>>i>>k;
    if (i==k)
    {
        cout<<"Y"<<endl<<i*k;
    }
    else
    {
        cout<<"N"<<endl<<i*k;
    }
    return 0;
}