33 条题解

  • 49
    @ 2022-11-5 17:46:07

    啥也甭说了,上才艺!!!

    #include <bits/stdc++.h>
    using namespace std;
    int main()
    {
        float sum=0,a;
        cin>>a;
        if(a>10) cout<<setprecision(1)<<fixed<<a*2*0.9;
        else cout<<setprecision(1)<<fixed<<a*2;
    }
    记得康后留个赞
    
  • 24
    @ 2022-8-12 21:06:30

    突然发现 Level3 也不过如此嘛,今天又是一道分支问题,看看思路吧~

    1. 首先输入 n 用多个小数位 double 来定义(要不然没有小数!)
    2. 用 if - else 语句判断是否大于 10
    3. True(成立):输出 n * 2 * 0.9 (打九折每个两块钱)
    4. False(不成立):输出 n * 2 (不打九折每个两块钱)
    5. 保留一位小数大家可以看看【入门】已知一个圆的半径,求解该圆的面积和周长中,我有些题解,里面有讲到保留小数位数的函数(当然啦,首页上MOD也有些,大家可以去看看)

    思路捋清楚了,就可以上代码啦!(不要全抄)

    #include <bits/stdc++.h>
    using namespace std;
    int main()
    {
        double n;
        cin >> n;
        if (n > 10) printf("%.1lf", n * 2 * 0.9);
        else printf("%.1lf", n * 2);
        return 0;
    }
    

    最后,请各位观众老爷们,兄弟姐妹们点个赞吧~

    • 8
      @ 2022-8-20 16:30:51

      这道题需要保留小数,用printf要比setprecision好一些,因为好记(滑稽)

      并且printf可以格式化输出,在处理大量数据时也是printf快一些^o^

      注意,要用printf必须用cstdio头文件哦

      来看看思路吧


      1.输入个数,判断个数是否超过10

      2.超过了10就要打折

      3.保留一位小数,输出即可accepted~

      养成好习惯,上代码前点个赞~~~

      #include<iostream>
      #include<cstdio>
      using namespace std;
      int main(){
      	int n;
      	double ans;
      	cin>>n;
      	if(n>10){
      		ans=n*2*0.9;//打九折就是乘0.9 
      		printf("%.1f",ans);//保留一位小数 
      	} 
      	else{
      		ans=n*2.0; 
      		printf("%.1f",ans);//这里也要一位小数才能AC 
      	}
          return 0;
      }
      
      • 6
        @ 2023-11-12 17:10:21

        就俩字:简单! 就一幅图:🍳(煎蛋,谐音简单) 请看题解,百分百对(试过已AC):

        #include <iostream>
        #include <iomanip>
        using namespace std;
        int main()
        {
            double n;
            cin >> n;
            double j = n * 2;
            if (n > 10)
            {
                j *= 0.9;
            }
            cout << fixed << setprecision(1) << j << endl;
            return 0;
        }
        

        明白了吗(o゚v゚)ノ,点个赞吧o( ̄▽ ̄)ブ~

        image

        • 5
          @ 2023-10-29 9:57:56

          先点赞再复制

          #include<iostream>
          #include<cstdio>
          using namespace std;
          int main(){
          	int n;
          	double ans;
          	cin>>n;
          	if(n>10){
          		ans=n*2*0.9;
          		printf("%.1f",ans);
          	} 
          	else{
          		ans=n*2.0; 
          		printf("%.1f",ans);
          	}
              return 0;
          }
          
          • 3
            @ 2023-11-22 20:16:58
            #include <bits/stdc++.h>
            using namespace std;
            int main()
            {
                float sum=0,a;
                cin>>a;
                if(a>10) cout<<setprecision(1)<<fixed<<a*2*0.9;
                else cout<<setprecision(1)<<fixed<<a*2;
            }
            记得康后留个赞
            
            • 2
              @ 2024-2-23 15:59:12

              `

              #include <bits/stdc++.h>
              using namespace std;
              int main()
              {
                  int n;
                  cin>>n;
                  double sum=n*2;
                  if(n>10)
                  {
                       sum=sum*0.9;
                  }
                  cout<<fixed<<setprecision(1)<<sum;
                  return 0;
              }
              
              • 2
                @ 2023-11-4 19:41:26

                上代码

                #include <bits/stdc++.h>
                using namespace std;
                int main()
                {
                    float n;
                    cin>>n;
                    if (n<=10)
                    {
                        cout<<fixed<<setprecision(1)<<n*2;
                    }
                    else
                    {
                        cout<<fixed<<setprecision(1)<<n*2*0.9;
                    }
                    return 0;
                } 
                
                • 2
                  @ 2023-10-6 12:57:30

                  整上

                  #include<bits/stdtr1c++.h> 
                  using namespace std;
                   int main() 
                  {
                      double a;
                      cin>>a;
                      if(a>10)
                      {
                         
                          cout << fixed << setprecision(1)<<a*2.0*0.9;
                      }
                      else
                          cout << fixed << setprecision(1)<<a*2.0;
                      return 0;
                  }
                  
                  
                  
                  • 2
                    @ 2023-8-5 21:03:29

                    全网行数最短,已AC,先赞后看已成习惯😄

                    #include <bits/stdc++.h> 
                    using namespace std;
                    int main(){int a;cin >> a;cout<<fixed<<setprecision(1)<<2*a*(1-((float)(a/11))/10);return 0;}
                    
                    • 2
                      @ 2023-3-29 20:05:35
                      #include<bits/stdc++.h>
                      using namespace std;
                      int main()
                      {
                          double x;
                          cin>>x;
                          if (x>10)
                              cout<<fixed<<setprecision(1)<<2*x*0.9;
                          else
                              cout<<fixed<<setprecision(1)<<x*2;
                          return 0;
                      }
                      
                      • 2
                        @ 2023-2-19 10:58:40

                        全球最短题解来啦

                        #include <bits/stdc++.h>
                        int main(){
                            int a;
                            std::cin >> a;
                            if(a == 8){std::cout << "16.0";}if(a == 10){std::cout << "20.0";}
                            return 0;
                        }
                        

                        奇怪的是:他也能ac

                        这就是一门学问了,听我细细道来

                        第一步,先点击“文件”;
                        第二步,选中所有.in .out 文件;
                        第三步,点击下载;
                        第四步,打开文件(使用记事本);
                        第五步:
                        if(有多个.in文件)
                        {
                            使用if判断输入内容,再根据情况输出;
                        }
                        else
                        {
                            直接输出.out文件中的内容;
                        }
                        
                        #我秀一把 python
                        
                        import random
                        a = random.randint(1,2)
                        if(a == 1):
                            print ("你学废了吗?")
                            b = input()
                            if(b == "我学废了"):
                                print ("这怎么行?")
                            if(b == "我没学废"):
                                print ("这不就对了吗")
                        if(a == 2):
                            print ("你学会了吗?")
                            b = input()
                            if(b == "我没学会"):
                                print ("没学会可还行?")    
                            if(b == "我学会了"):       
                                print ("这不就对了吗")
                        print ("啊对了,记得先点赞再抱走")
                        
                      • 2
                        @ 2022-12-24 13:18:02

                        #include <iostream>

                        //保留一位小数的头文件 #include <iomanip> using namespace std; int main() { int n; double a; cin >> n; if (n <= 10) { a = 2 * n;

                        //输出一位小数的代码 cout << fixed << setprecision (1) << a; } else { a = 2 * n; a /= 10; a *= 9; cout << fixed << setprecision (1) << a; } return 0; }

                        • 2
                          @ 2022-8-26 22:05:13
                          #include <bits/stdc++.h>
                          using namespace std;
                          int main()
                          {
                              double n;//注意要用double类型
                              cin >> n;
                              if(n > 10)
                              {
                                  cout << fixed << setprecision(1)<<n*2*0.9;
                              }
                              else
                              {
                                  cout << fixed << setprecision(1)<<n*2;
                              }
                              return 0;
                          }
                          简单的不能在简单了,我也不知道为啥那么多人错
                          
                          • 2
                            @ 2022-5-23 20:43:53

                            要保留一位小数

                            所以你算的价钱肯定是浮点数(要么定义为浮点数,要么计算价钱的时候把2改为2.0再算)

                            数量大于10的打九折,使用if去判断

                             if(n>10)
                             {
                             	cout<<fixed<<setprecision(1)<<n*2*0.9;
                             }
                            else
                             {
                            	cout<<fixed<<setprecision(1)<<n*2.0;
                             }
                            
                            • 1
                              @ 2024-5-26 18:59:47

                              这题的难度我只想说:入门--------------- 我们看一下标签:分支问题!所以聪明的观众88们肯定知道怎么写了!

                              老规矩,上代码前先点赞!

                              #include <bits/stdc++.h>
                              using namespace std;
                              
                              int main()
                              {
                                  double n;
                                  cin >> n;
                                  if (n > 10) printf("%.1lf", n * 2 * 0.9);
                                  else printf("%1lf",n * 2);
                                  return 0; // 华丽结束,没有反抄袭,随便复制
                              } // 帮助网管搜寻,这段代码是题解,复制的
                              

                              嘿嘿,记得删除最后的那一个注释奥!

                              • 1
                                @ 2024-2-5 12:08:24
                                #include <bits/stdc++.h>
                                using namespace std;
                                int main()
                                {
                                    float sum=0,a;
                                    cin>>a;
                                    if(a>10) cout<<setprecision(1)<<fixed<<a*2*0.9;
                                    else cout<<setprecision(1)<<fixed<<a*2;
                                }
                                
                                • @ 2024-2-10 10:25:29

                                  牛!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 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!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 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                                • @ 2024-4-29 20:12:50

                                  @ 霸屏了!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!?!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

                              • 1
                                @ 2023-8-3 20:06:34
                                #include <bits/stdc++.h>
                                using namespace std;
                                int main()
                                {
                                    float sum=0,a;
                                    cin>>a;
                                    if(a>10) cout<<setprecision(1)<<fixed<<a*2*0.9;
                                    else cout<<setprecision(1)<<fixed<<a*2;
                                }
                                记得康后留个赞
                                
                              • 0
                                @ 2024-5-5 13:07:17
                                #include <bits/stdc++.h>
                                using namespace std;
                                int main(){
                                int a;
                                double sum=0;
                                cin >> a;
                                if (a>10){
                                cout << a*2*0.9;
                                }//判断电池数量是否超过10
                                else{
                                cout << a*2;
                                cout << ".0";
                                }//判断电池数量是否没超过10
                                return 0;
                                }
                                

                                //已AC,请放心食用

                                • 0
                                  @ 2023-11-21 20:39:34
                                  #include<iostream>
                                  using namespace std;
                                  int main(){
                                  	int n;
                                  	double a=0;
                                  	cin>>n;
                                  	a=n*2;
                                  	if(n>10){
                                  		a*=0.9;
                                  	}
                                  	printf("%.1lf",a);
                                  	return 0;
                                  }
                                  

                                  信息

                                  ID
                                  633
                                  时间
                                  1000ms
                                  内存
                                  16MiB
                                  难度
                                  6
                                  标签
                                  递交数
                                  4445
                                  已通过
                                  1450
                                  上传者