#include<iostream> using namespace std; int main() {

int n,a,x;
cin >> n >> a >> x;
cout << n - a * x;
return 0;

}

• #include <bits/stdc++.h>
  using namespace std;
  int main()
  {
      int n, a, x;
      cin >> n >> a >> x;
      cout << n - a * x;
      return 0;
  }
  

  Copy *

//python 3 来了 n = int(input()) a = int(input()) x = int(input()) z = 0 for i in range(x): z = z + a n = n - z print(n)

米老鼠不会偷糖果 《关于米老鼠和厨房里的糖果的一件事》

#include <iostream>
using namespace std;
int main()
{
    //我对米老鼠说：“你来错地方了，这里没有糖果。”
    cout << 0 << endl;
    return 0;
}

只是开个玩笑而已嘛，何必当真呢？

cout << n - a * x;

#include <iostream>
using namespace std;
int main()
{
int n,a,x;//定义
cin >>n>>a>>x;//输入
cout <<n-x*a;//输出用总糖果数减去偷的糖果数（奇奇怪怪的米老鼠）
return 0;
}

来力！！！！ python3

p=int(input())
o=int(input())
i=int(input())
o=o*i
p=p-o
print(p)

#include<iostream> using namespace std; int main() { int n,a,x; cin>>n>>a>>x; if(n-ax<=0) cout<<0<<endl; else cout<<n-ax<<endl; return 0; }

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int n, a, x;
    cin >> n >> a >> x;
    cout << n - a * x;
    return 0;
}

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int n, a, x;
    cin >> n >> a >> x;
    cout << n - a * x;
    return 0;
}

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int n,a,x;
    cin >> n>>a>>x;
	cout << n-a*x;
    return 0;
}

aaaaaa

jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

非常简单

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int a,n,x,sum=0;
    cin >> n >> a >> x  ;
    sum=n-a*x;
    cout<<sum;
    return 0;
}

题解：简单数学知识，n-a*x，计算剩余数量。

#include <bits/stdc++.h> using namespace std; int main() { int n, a, x; cin >> n >> a >> x; cout << n - a * x;

return 0;

}

有手就行

#include <bits/stdc++.h> using namespace std; int main() { int n,a,x; cin >> n >> a >> x; cout << n - a * x;//总量-每次数*次数 return 0; }