61 条题解
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-1
hetao6018520 LV 7 @ 2023-1-20 16:02:38
#include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; if (n%2==1) { cout << n/2+1; } else { cout << n+1; } return 0; } -
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最短行
#include <iostream> using namespace std; int main() { int n; cin >> n; if(n%2==1) cout << n/2+1; else cout << n/2+n/2+1; }-
hetao348339
@ 2023-2-16 18:32:36
OMG
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-1
hetao1390276 LV 7 @ 2022-9-30 21:36:58
这个题必须要用万能头文件 代码开始 #include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; if (n%2==1) { cout << n/2+1; } else { cout << n+1; } return 0; }
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-1
hetao10292628 LV 9 @ 2022-8-31 10:35:22
#include<iostream> using namespace std; int main() { int n; cin>>n; if(n%2==0) { cout<<n/2+1+n/2; } else { cout<<n/2+1; } return 0; } -
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hetao3046622 LV 6 @ 2022-8-19 9:18:16
#include <iostream> using namespace std; int main(){ int n; cin>>n; if (n%2==1){ cout<<(n+1)/2; } if (n%2==0){ cout<<n/2+n/2+1; } return 0; } -
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hetao1717856 LV 7 @ 2022-8-13 16:49:30
if (n%2 == 0) cout << n+1; else cout << n/2+1; -
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题解：n为奇数中间数为n/2+1,n为偶数中间数是n/2和n/2+1,两个数求和化简为n+1。
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hetao2940092
@ 2022-5-29 16:00:07
可以上代码吗？(q^_^q)
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-2
hetao37288042 LV 6 @ 2024-1-3 20:41:48
#include <iostream> using namespace std; int main() { int n,p = 0; cin >> n; if (n % 2 == 1) { p = n / 2 + 1; } else { p = n + 1; } cout << p << endl; return 0; } -
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hetao5633061
LV 7
@ 2024-1-1 23:15:40
#include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; if (n % 2 == 1) { cout << (n + 1) / 2; } else { cout << n + 1; } return 0; }点个赞吧
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hetao2132750 LV 5 @ 2024-1-1 19:42:05
#include <iostream> using namespace std; int main () { int n,sum=0; cin>>n; if (n%2==1) { sum+=n/2+1; } else { sum+=n/2+n/2+1; } cout<<sum; return 0;
}
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-3
hetao3720240 LV 6 @ 2022-9-12 17:00:14
if语句 #include <iostream> using namespace std; int n; int main() { cin >> n; if (n % 2 == 1) { cout << (n+1) / 2; } else { cout << 2 * (n/2) + 1; } }
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hetao4963622 LV 6 @ 2022-8-23 20:39:00
#include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; if (n % 2 == 1)//判断奇偶数 { cout << n / 2 + 1;//找规律 } else { cout << n + 1;//找规律 } return 0; }
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hetao830727 LV 6 @ 2022-7-20 11:14:25
#include <iostream> using namespace std; int main() { int n; cin >> n; if (n%2 == 1) { cout << (n+1)/2; } else { cout << n+1; } return 0; } -
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hetao3097453
LV 10
@ 2022-7-6 7:23:55
if(n % 2 == 0)//偶数情况 { cout << n + 1; } else//奇数情况 { cout << n / 2 + 1; } -
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hetao3390719 LV 8 @ 2022-6-12 12:23:27
#include <iostream> using namespace std; int main() { int a; int sum=0; cin >> a; for(int i=1;i<=a;i++) { sum += i*i; } cout << sum ; return 0; }
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hetao6023425 LV 6 @ 2022-6-10 23:05:47
#include<iostream> using namespace std; int main() { int n; cin >> n; if (n%2==1) { cout << n/2+1; } else { cout << n+1; } return 0; }
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-6
13524456534 LV 7 @ 2022-8-23 18:57:44
#include<iostream> using namespace std; int main() { int n; cin>>n; if(n%2==1)//判断奇偶数 { cout<<( );//输出中间数 } else { cout<<( );//输出两数之和 } return 0; }-
这题的输出和计算是关键 提示: 奇数可以+1使其变成偶数
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hetao5166917
LV 7
@ 2022-8-22 21:08:46
嘻嘻，简洁的代码来喽！！
#include<bits/stdc++.h> using namespace std; int main(){ int n; cin >> n; if(n % 2 == 1) cout << n / 2 + 1 << endl; else cout<< n + 1 << endl; return 0; }
