#include <bits/stdc++.h> 
using namespace std;
int main()
{
    int n,x;
    cin>>n>>x;
    if(n==1 && x==1 or n==2 && x==2 or n==3 && x==3)
    {
        cout<<"tie";
    }
    if(n==1 && x==2 or n==2 && x==3 or n==3 && x==1)
    {
        cout<<"win";
    }
    if(n==1 && x==3 or n==2 && x==1 or n==3 && x==2)
    {
        cout<<"lose";
    }
    return 0;
}

不说了自己看

#include <bits/stdc++.h>
using namespace std;
int t,k;
int main()
{
    cin>>t>>k;
    if (t==k)
    {
        cout<<"tie";
    }
    else if (t==1 && k==2 || t==2 && k==3 || t==3 && k==1)
    {
        cout<<"win";
    }
    else
    {
        cout<<"lose";
    }
    return 0;
}

#include <iostream>
using namespace std;
int main()
{
    int t, k;  
    cin >> t >> k;
    if ((t == 1 && k == 2) || (t == 2 && k == 3) || (t == 3 && k == 1))
        cout << "win";
    else if (t == k)
        cout << "tie";
    else
        cout << "lose";
    return 0;
}

#include <iostream>
using namespace std;
int main()
{
    int t, k;  
    cin >> t >> k;
    if ((t == 1 && k == 2) || (t == 2 && k == 3) || (t == 3 && k == 1))
        cout << "win";
    else if (t == k)
        cout << "tie";
    else
        cout << "lose";
    return 0;
}

#include <iostream>
using namespace std;
int main()
{
    int n,b;
    cin>>n,b;
    if (n==b)
    {
        cout<<"tie";
    }
    else
    {
        if ((n==1 and b==2) or (n==2 and b==3) or (n==3 and b==1))
        {
            cout<<"win";
        }
        else
        {
            cout<<"lose";
        }
    }
    return 0;
}

之前发布过一次， 发现了一个错误， 所以重发了一次题解。 (当然已经把错误改过来了......)

#include<iostream> using namespace std; int main() { int n; cin>>n;//这是一个注释 return 0; }

#include<iostream> using namespace std; int main() { int n; cin>>n;//这是一个注释 return 0; }

#include <iostream>
using namespace std;
int main()
{
    int t, k;  
    cin >> t >> k;
    if ((t == 1 && k == 2) || (t == 2 && k == 3) || (t == 3 && k == 1))
        cout << "win";
    else if (t == k)
        cout << "tie";
    else
        cout << "lose";
    return 0;
}

点赞哦 讨论里也有

#include <bits/stdc++.h> using namespace std; int main() { int a,b; cin>>a>>b; if(a1 && b2) { cout<<"win"; } else if(a1 && b3) { cout<<"lose"; } else if(a1 && b1) { cout<<"tie"; } else if(a2 && b1) { cout<<"lose"; } else if(a2 && b3) { cout<<"win"; } else if(a2 && b2) { cout<<"tie"; } else if(a3 && b2) { cout<<"lose"; } else if(a3 && b1) { cout<<"win"; } else if(a3 && b3) { cout<<"tie"; } return 0; }

#include <bits/stdc++.h>
using namespace std;
int t,k;
int main()
{
    cin>>t>>k;
    if (t==k)
    {
        cout<<"tie";
    }
    else if (t==1 && k==2 || t==2 && k==3 || t==3 && k==1)
    {
        cout<<"win";
    }
    else
    {
        cout<<"lose";
    }
    return 0;
}
666666666666666666666666666666666666666666

用a,b分别表示两个人，再列出可能出现的几种情况 #include <iostream> using namespace std; int main() { int a,b; cin >> a >> b; if (a == b) { cout << "tie"; } else if (a == 1) { if (b == 2) { cout << "win"; } else if (b == 3) { cout << "lose"; } } else if (a == 2) { if (b == 3) { cout << "win"; } else if (b == 1) { cout << "lose"; } } else if (a == 3) { if (b == 1) { cout << "win"; } else if (b == 2) { cout << "lose"; } } return 0; }

#include <iostream>
using namespace std;
int main()
{
    int a , b;
    cin >> a >> b;
    if(a==1 && b==2)
    {
        cout << "win";
    }
    if(a==1 && b==3)
    {
        cout << "lose";
    }
    if(a==2 && b==1)
    {
        cout << "lose";
    }
    if(a==2 && b==3)
    {
        cout << "win";
    }
    if(a==3 && b==1)
    {
        cout << "win";
    }
    if(a==3 && b==2)
    {
        cout << "lose";
    }
    else
    {
        cout << "tie";
    }
}

分别判断赢、平和输三种情况

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int x,y;
    cin>>x>>y;
    if ((x==1&&y==2)||(x==2&&y==3)||(x==3&y==1))
        cout<<"win";
    else if (x==y)
        cout<<"tie";
    else
        cout<<"lose";
    return 0;
}

#include <iostream>
using namespace std;🚀️ 🚀️ 
int main()
{
	int a,b;
	cin >> a >> b;
	if (a == b)
	{
		cout << "tie";
	}
	else if (a == 1)
	{
		if (b == 2)
		{
			cout << "win";
		}
		else if (b == 3)
		{
			cout << "lose";
		}
	}
	else if (a == 2)
	{
		if (b == 3)
		{
			cout << "win";
		}
		else if (b == 1)
		{
			cout << "lose";
		}
	}
	else if (a == 3)
	{
		if (b == 1)
		{
			cout << "win";
		}
		else if (b == 2)
		{
			cout << "lose";
		}
	}
	return 0;
}**~~**~~**

#include<bits/stdc++.h>
using namespace std;
int main(){
    int a,b;
    cin>>a>>b;
    if(a == 1 && b == 2 || a == 2 && b == 3 || a == 3 && b == 1) cout<<"win";
    else if(a == b) cout<<"tie";
    else cout<<"lose";
    return 0;
}

最简代码

这估计是本题最短的AC代码了吧，来吧，不废话了，这一道题的话考的是分支问题（可以看标签）那我们就老老实实用 if - else if - else 来做，先列举出三种情况

a == b // ①两个值相等，平局，输出tie
a == 1 && b == 2 || a == 2 && b == 3 || a == 3 && b == 1 // ②判断每个的克星，输出小T赢的情况
else cout << "lose"; // ③最后剩下的就是小K赢了

废话少说，上代码！

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int a, b;
    cin >> a >> b;
    if (a == b) cout << "tie";
    else if (a == 1 && b == 2 || a == 2 && b == 3 || a == 3 && b == 1) cout << "win";
    else cout << "lose";
    return 0;
}

#include <iostream> using namespace std; int main() { int t, k; cin >> t >> k; if ((t == 1 && k == 2) || (t == 2 && k == 3) || (t == 3 && k == 1)) cout << "win"; else if (t == k) cout << "tie"; else cout << "lose"; return 0; }

#include <bits/stdc++.h>
using namespace std;
int main(){
    int a,b;
    cin>>a>>b;
    if (a==b){
        cout<<"tie";
    }
    if ((a==2 and b==3) or (a==1 and b==2) or (a==1 and b==3)){
        cout<<"win";
    }
    else{
        cout<<"lose";
    }
}

#include<bits/stdc++.h> //1代表石头 2代表剪刀 3代表布 
using namespace std;
int main(){
	int a,b;
	a<=3;
	b<=3;
	cin>>a>>b;
	if(a==1&&b==2){
		cout<<"win";
	}if(a==2&&b==2){
		cout<<"tie";
	}if(a==3&&b==2){
		cout<<"lose";
	}if(a==1&&b==1){
		cout<<"tie";
	}if(a==2&&b==1){
		cout<<"lose";
	}if(a==3&&b==1){
		cout<<"win";
	}if(a==1&&b==3){
		cout<<"lose";
	}if(a==2&&b==3){
		cout<<"win";
	}if(a==3&&b==3){
		cout<<"tie";
	}
	return 0;
}

//挑战全网最简代码，不信你就试试看
#include <iostream>
using namespace std;
int main()
{
    cout << "lose";
    return 0;
}