-
个人简介
1.判断质数
bool prime(int n){ if (n <= 1) return false; if (n == 2) return true; if (n % 2 == 0) return false; for (int i = 3; i <= sqrt(n); i += 2) { if (n % i == 0) return false; } return true; }
2.判断回文数
bool palindrome(int n){ std::string s = std::to_string(n); int l=0; int r=s.length()-1; while (l<r){ if (s[l]!=s[r]) return false; l++; r--; } return true; }
-
通过的题目
-
最近活动
This person is lazy and didn't join any contests or homework. -
最近编写的题解
This person is lazy and didn't write any solutions.
题目标签
- 客观题
- 1